Question

已知集合A={x|x²-4x＞0},B={x||x-1|≤2},那么集合A∩B等于

A.{x|-1≤x＜0}                               B.{x|3≤x＜4}

C.{x|0＜x≤3}                                D.{x|-1≤x＜0或3≤x＜4}

Answer 1

A

解析:由x²-4x＞0,得x＜0或x＞4,即A={x|x＜0或x＞4};由|x-1|≤2,得-2≤x-1≤2,-1≤x≤3,即B={x|-1≤x≤3}.∴A∩B={x|-1≤x＜0}.