题目内容
若| a |
| a |
| a |
| a |
| ||
| 3 |
| ||
| 3 |
| a |
| a |
| a |
| 3 |
| 6 |
分析:若
1=(
,
),
=(
,
),
=(
,
),则
1+
2+
3=(
,
)不成立;若
1,
2,
3均为单位向量,
1+
2+
3=(
,
)?
1=(
,
).由此能得到正确答案.
| a |
| ||
| 3 |
| ||
| 3 |
| a2 |
| ||
| 3 |
| ||
| 3 |
| a3 |
| 1 |
| 2 |
| ||
| 2 |
| a |
| a |
| a |
| 3 |
| 6 |
| a |
| a |
| a |
| a |
| a |
| a |
| 3 |
| 6 |
| a |
| ||
| 3 |
| ||
| 3 |
解答:解:
1,
2,
3均为单位向量,
1=(
,
),
若
=(
,
),
=(
,
),则
1+
2+
3=(
,
)不成立;
若
1,
2,
3均为单位向量,
1+
2+
3=(
,
)?
1=(
,
).
所以
1=(
,
)是
1+
2+
3=(
,
)的必要不充分条件.
故答案为:必要不充分.
| a |
| a |
| a |
| a |
| ||
| 3 |
| ||
| 3 |
若
| a2 |
| ||
| 3 |
| ||
| 3 |
| a3 |
| 1 |
| 2 |
| ||
| 2 |
| a |
| a |
| a |
| 3 |
| 6 |
若
| a |
| a |
| a |
| a |
| a |
| a |
| 3 |
| 6 |
| a |
| ||
| 3 |
| ||
| 3 |
所以
| a |
| ||
| 3 |
| ||
| 3 |
| a |
| a |
| a |
| 3 |
| 6 |
故答案为:必要不充分.
点评:本题考查必要条件、充分条件、充要条件的性质和应用,解题时要全面考虑,避免出现不必要的错误.
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