题目内容
已知向量
=(2,-1),
=(3,-2)求(3
-
)•(
-2
)
| a |
| b |
| a |
| b |
| a |
| b |
∵
•
=2×3+(-1)×(-2)=8,
2=22+(-1)2=5,
2=32+(-2)2=13,
∴(3
-
)•(
-2
)=3
2-7
•
+2
2=3×5-7×8+2×13=-15.
| a |
| b |
| a |
| b |
∴(3
| a |
| b |
| a |
| b |
| a |
| a |
| b |
| b |
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