Question

不等式

|x+1|

|x+2|

≥1的实数解为 ______．

Answer 1

|x+1|

|x+2|

≥1?

|x+1|≥|x+2 x+2≠0

?

(x+1)2≥(x+2)2 x+2≠0

?x≤-

3

2

且x≠-2
故答案为：x≤-

3

2

且x≠-2