Question

设函数f(x)＝log_ax(a＞0且a≠1)，若f(x₁x^₂…x₂₀₀₈)＝8，则f(x₁²)+f(x^₂2)+…+f(x₂₀₀₈²)的值为

1. A.
   4
2. B.
   8
3. C.
   16
4. D.
   2log_a8

Answer 1

C
由题意得log_ax₁+log_ax₂+…+log_ax₂₀₀₈＝8，则f(x₁²)+f(x₂²)+…+f(x₂₀₀₈²)＝2log_ax₁+2log_ax₂+…+2log_ax₂₀₀₈＝16．