Question

lg5•log

10

²⁰+(lg2

2

)2-3log32-1．

Answer 1

lg5•log

10

²⁰+(lg2

2

)2-3log32-1．
=lg5•（2lg20）+(lg2

2

)2-

3log32

3

=2（1-lg2）•（1+lg2）+2lg²2-

2

3

=2-

2

3

=

4

3