题目内容
要得到y=cos2x的图象,只要将y=sin(2x+
)的图象向右平移最少______个单位长度.
| π |
| 4 |
∵y=cos2x=sin(
+2x)=sin(2x-
)=sin2(x-
),
函数y=sin(2x+
)=sin2(x+
),
-(-
)=
,
故将y=sin(2x+
)的图象向右平移最少
个单位,可得函数y=sin2(x-
)=cos2x 的图象,
故答案为
.
| π |
| 2 |
| 3π |
| 2 |
| 3π |
| 4 |
函数y=sin(2x+
| π |
| 4 |
| π |
| 8 |
| π |
| 8 |
| 3π |
| 4 |
| 7π |
| 8 |
故将y=sin(2x+
| π |
| 4 |
| 7π |
| 8 |
| 3π |
| 4 |
故答案为
| 7π |
| 8 |
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