题目内容
已知向量
,
满足|
|=1,
=2,(
-
)•
=0,则
与
的夹角为______.
| a |
| b |
| a |
| b |
| a |
| b |
| a |
| a |
| b |
∵已知向量
,
满足|
|=1,|
|=2,(
-
)•
=0,
∴
2=
•
,∴1=1×2×cos<
,
>,∴cos<
,
>=
,
∴<
,
>=
,
故答案为
.
| a |
| b |
| a |
| b |
| a |
| b |
| a |
∴
| a |
| a |
| b |
| a |
| b |
| a |
| b |
| 1 |
| 2 |
∴<
| a |
| b |
| π |
| 3 |
故答案为
| π |
| 3 |
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已知向量a,b满足|a|=2,|b|=3,|2a+b|=
,则a与b的夹角为( )
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