题目内容

已知平面上不共线的四点O,A,B,C.若
OA
+2
OC
=3
OB
,则
|BC|
|AB|
的值为(  )
A.
1
2
B.
1
3
C.
1
4
D.
1
6
OA
+2
OC
=3
OB

∴移项整理,得
OA
-
OB
=2(
OB
-
OC
)

OA
-
OB
=
BA
OB
-
OC
=
CB

BA
=2
CB

∴由此可得
|BC|
|AB|
=
|CB|
|BA|
=
1
2

故选:A
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