题目内容
在△ABC中,A、B、C的对边分别为a、b、c,
(Ⅰ)化简:bcosC+ccosB;
(Ⅱ)求证:
-
=
-
.
(Ⅰ)化简:bcosC+ccosB;
(Ⅱ)求证:
| cos2A |
| a2 |
| cos2B |
| b2 |
| 1 |
| a2 |
| 1 |
| b2 |
(Ⅰ)bcosC+ccosB=b•
+c•
=
+
=a
(II)证明:∵
-
=
=
=4R2(R为三角形外接圆的半径)
-
=
=
=4R2
∴
-
=
-
∴
-
=
-
.
| a2+b2-c2 |
| 2ab |
| a2+c2-b2 |
| 2ac |
=
| a2+b2-c2 |
| 2a |
| a2+c2-b2 |
| 2a |
=a
(II)证明:∵
| 1 |
| a2 |
| cos2A |
| a2 |
| 1-cos2A |
| a2 |
| sin2A |
| a2 |
| 1 |
| b2 |
| cos2B |
| b2 |
| 1-cos2B |
| b2 |
| sin2B |
| b2 |
∴
| 1 |
| a2 |
| cos2A |
| a2 |
| 1 |
| b2 |
| cos2B |
| b2 |
∴
| cos2A |
| a2 |
| cos2B |
| b2 |
| 1 |
| a2 |
| 1 |
| b2 |
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