题目内容
| 1 |
| n |
| 1 |
| 1 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 6 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 12 |
分析:据每个数是它下一行左右相邻两数的和,先求出第7,8,9三行的第2个数,再求出8,9两行的第3个数,求出第9行的第4个数.
解答:解:设第n行第m个数为a(n,m),
由题意知a(6,1)=
,a(7,1)=
,a(8,1)=
,a(9,1)=
∴a(7,2)=a(6,1)-a(7,1)=
,a(8,2)=a(7,1)-a(8,1)=
,a(9,2)=a(8,1)-a(9,1)=
,
a(8,3)=a(7,2)-a(8,2)=
,a(9,3)=a(8,2)-a(9,2)=
a(9,4)=a(8,3)-a(9,3)=
故选C
由题意知a(6,1)=
| 1 |
| 6 |
| 1 |
| 7 |
| 1 |
| 8 |
| 1 |
| 9 |
∴a(7,2)=a(6,1)-a(7,1)=
| 1 |
| 42 |
| 1 |
| 56 |
| 1 |
| 72 |
a(8,3)=a(7,2)-a(8,2)=
| 1 |
| 118 |
| 1 |
| 252 |
a(9,4)=a(8,3)-a(9,3)=
| 1 |
| 504 |
故选C
点评:本题考查归纳推理,解题的关键是通过观察分析归纳各数的关系,考查学生的观察分析和归纳能力,属中档题.
练习册系列答案
相关题目
| A、580 | B、577 | C、576 | D、574 |