题目内容
已知向量
,
满足|
|=|
|=3,
•
=0,则|
+
|值为( )
| a |
| b |
| a |
| b |
| a |
| b |
| a |
| b |
| A.1 | B.3
| C.2
| D.2 |
∵
•
=0,
∴|
+
|2=
2+2
•
+
2=
2+
2
又∵|
|=|
|=3,可得
2=
2=9
∴|
+
|2=9+9=18,可得|
+
|=
=3
故选:B
| a |
| b |
∴|
| a |
| b |
| a |
| a |
| b |
| b |
| a |
| b |
又∵|
| a |
| b |
| a |
| b |
∴|
| a |
| b |
| a |
| b |
| 18 |
| 2 |
故选:B
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