题目内容
计算下列各式值
(1)(2x)
(-3x
y-
)÷[(-27)
x-
y-
](2)log2
+log212-
log242.
(1)(2x)
| 1 |
| 4 |
| 1 |
| 4 |
| 1 |
| 3 |
| 2 |
| 3 |
| 1 |
| 2 |
| 2 |
| 3 |
|
| 1 |
| 2 |
分析:(1)直接利用有理数的指数幂的运算法则求解即可.
(2)直接利用对数的运算法则求解即可.
(2)直接利用对数的运算法则求解即可.
解答:解:(1)(2x)
(-3x
y-
)÷[(-27)
x-
y-
]
=-(2
×31-3×
)•x
+
+
•y-
+
=-
x
.
(2)log2
+log212-
log242=
-
+
-
=
-
-
+
+
-
-
-
=-
×4+2-
=-
.
| 1 |
| 4 |
| 1 |
| 4 |
| 1 |
| 3 |
| 2 |
| 3 |
| 1 |
| 2 |
| 2 |
| 3 |
=-(2
| 1 |
| 4 |
| 2 |
| 3 |
| 1 |
| 4 |
| 1 |
| 4 |
| 1 |
| 2 |
| 1 |
| 3 |
| 2 |
| 3 |
=-
| |||
| 3 |
| 3 | y |
(2)log2
|
| 1 |
| 2 |
| 1 |
| 2 |
| log | 7 2 |
| 1 |
| 2 |
| log | (24×3) 2 |
| log | (22×3) 2 |
| 1 |
| 2 |
| log | (2×3×7) 2 |
=
| 1 |
| 2 |
| log | 7 2 |
| 1 |
| 2 |
| log | 24 2 |
| 1 |
| 2 |
| log | 3 2 |
| log | 22 2 |
| log | 3 2 |
| 1 |
| 2 |
| log | 2 2 |
| 1 |
| 2 |
| log | 3 2 |
| 1 |
| 2 |
| log | 7 2 |
=-
| 1 |
| 2 |
| 1 |
| 2 |
=-
| 1 |
| 2 |
点评:本题考查指数幂的运算,对数的运算法则,考查基本知识的掌握情况,考查计算能力.
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