题目内容

求和:1+
4
5
+
7
52
+…+
3n-2
5n-1
设Sn=1+
4
5
+
7
52
+…+
3n-5
5n-2
+
3n-2
5n-1
   ①?
1
5
Sn=
1
5
+
4
52
+
7
53
+…+
3n-5
5n-1
+
3n-2
5n
     ②?
①-②得:?
4
5
Sn=1+
3
5
+
3
52
+…+
3
5n-1
-
3n-2
5n

=1+3×
1
5
(1-
1
5n-1
)
1-
1
5
-
3n-2
5n

=
5n-12n-7
5n

∴Sn=
5n-12n-7
16×5n-1
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