题目内容
计算:
(1)lg500+lg
-
lg64+log23•log34
(2)0.0081-
-[3×(
)0]-1×[81-0.25+(3
)-
]-
.
(1)lg500+lg
| 8 |
| 5 |
| 1 |
| 2 |
(2)0.0081-
| 1 |
| 4 |
| 7 |
| 8 |
| 3 |
| 8 |
| 1 |
| 3 |
| 1 |
| 2 |
分析:(1)直接利用对数的运算性质求解即可.
(2)通过有理指数幂的运算,直接求解即可.
(2)通过有理指数幂的运算,直接求解即可.
解答:解:(1)lg500+lg
-
lg64+log23•log34=2+lg5+3lg2-lg5-3lg2+2=4.
(2)0.0081-
-[3×(
)0]-1×[81-0.25+(3
)-
]-
=0.3-1-3-1×[3-1+(
)-1] -
=
-
=3.
| 8 |
| 5 |
| 1 |
| 2 |
(2)0.0081-
| 1 |
| 4 |
| 7 |
| 8 |
| 3 |
| 8 |
| 1 |
| 3 |
| 1 |
| 2 |
=0.3-1-3-1×[3-1+(
| 3 |
| 2 |
| 1 |
| 2 |
=
| 10 |
| 3 |
| 1 |
| 3 |
=3.
点评:本题考查对数与指数的运算法则的应用,考查计算能力.
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