题目内容
已知函数f(x)满足f(
)=2,f′(
)=4,则函数F(x)=f(x)•sinx的图象在x=
处切线的斜率为______.
| π |
| 4 |
| π |
| 4 |
| π |
| 4 |
F'(x)=f'(x)•sinx+f(x)•cosx
∵f(
)=2,f′(
)=4,sin
=cos
=
∴F'(
)=f'(
)•sin
+f(
)•cos
=3
故答案为:3
.
∵f(
| π |
| 4 |
| π |
| 4 |
| π |
| 4 |
| π |
| 4 |
| ||
| 2 |
∴F'(
| π |
| 4 |
| π |
| 4 |
| π |
| 4 |
| π |
| 4 |
| π |
| 4 |
| 2 |
故答案为:3
| 2 |
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