题目内容
如图所示,已知△ABC中,D、E、F分别是![]()
求证:(1)DE∥AB;
(2)DE=
AB;
(3)
+
+
=0.
证明:由![]()
![]()
![]()
,可得(1)(2).
(3)取
=e1,
=e2,则
=![]()
=
(
+
)=e2+e1,
=
+
=-2e1+e2+e1=e2-e1,
=2e1+e2,
=-e1-2e2,
故
+
+
=0.
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题目内容
如图所示,已知△ABC中,D、E、F分别是![]()
求证:(1)DE∥AB;
(2)DE=
AB;
(3)
+
+
=0.
证明:由![]()
![]()
![]()
,可得(1)(2).
(3)取
=e1,
=e2,则
=![]()
=
(
+
)=e2+e1,
=
+
=-2e1+e2+e1=e2-e1,
=2e1+e2,
=-e1-2e2,
故
+
+
=0.