题目内容

已知双曲线W的左、右焦点分别为,点,右顶点是M,且

(Ⅰ)求双曲线的方程;

(Ⅱ)过点的直线l交双曲线W的右支于AB两个不同的点(BAQ之间),若点在以线段AB为直径的圆的外部,试求△AQH与△BQH面积之比λ的取值范围.

 

【答案】

(1);(2).

【解析】(1)利用双曲线的基本量的运算和向量的数量积可得。(2)设出直线l的方程,要注意斜率存在且不为0,直线方程与双曲线方程联立利用判别式和韦达定理,点在以线段AB为直径的圆的外部,就是,得可得,再转化为横坐标运算,整理得,由求出

解:(Ⅰ)由已知

,则,∴,∴

解得,∴双曲线的方程为.·································· 4分

(Ⅱ)直线l的斜率存在且不为0,设直线l:,设

,则

解得.     ①································································· 6分

∵点在以线段AB为直径的圆的外部,则

,解得.  ②

由①、②得实数k的范围是,······················································· 8分

由已知,∵BAQ之间,则,且

,则,∴

,··················································· 10分

,∴,解得,又,∴

λ的取值范围是.···································································· 13分

 

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