题目内容
求值:
(1)[(-5)4]
-(15)0;
(2)[(3
)-
•(5
)0.5+(0.008)-
÷(0.02)-
×(0.32)
]÷0.06250.25;
(3)已知a
+a-
=3,求a
+a-
.
(1)[(-5)4]
| 1 |
| 4 |
(2)[(3
| 3 |
| 8 |
| 2 |
| 3 |
| 4 |
| 5 |
| 2 |
| 3 |
| 1 |
| 2 |
| 1 |
| 2 |
(3)已知a
| 1 |
| 2 |
| 1 |
| 2 |
| 3 |
| 2 |
| 3 |
| 2 |
分析:分别利用分数指数幂的运算法则,求得各个式子的值.
解答:解:(1)[(-5)4]
-(15)0 =5-1=4;
(2)[(3
)-
•(5
)0.5+(0.008)-
÷(0.02)-
×(0.32)
]÷0.06250.25 ={ [(
)3]-
×(
)
+[ 0.23]-
÷50
×(
)
}÷ [(
)4]0.25
=[
×
+25×
×
]÷2=(
+2)÷2=
+1.
(3)∵a
+a-
=3,
∴a
+a-
=(a
+a-
)( a-1+a-1)=3(a-1+
)=3[( a
+a-
) 2-3]=3(9-3)=18.
| 1 |
| 4 |
(2)[(3
| 3 |
| 8 |
| 2 |
| 3 |
| 4 |
| 5 |
| 2 |
| 3 |
| 1 |
| 2 |
| 1 |
| 2 |
| 3 |
| 2 |
| 2 |
| 3 |
| 29 |
| 5 |
| 1 |
| 2 |
| 2 |
| 3 |
| 1 |
| 2 |
| 32 |
| 100 |
| 1 |
| 2 |
| 1 |
| 2 |
=[
| 4 |
| 9 |
| ||
| 5 |
| 1 | ||
|
2
| ||
| 5 |
4
| ||
| 45 |
2
| ||
| 45 |
(3)∵a
| 1 |
| 2 |
| 1 |
| 2 |
∴a
| 3 |
| 2 |
| 3 |
| 2 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| a |
| 1 |
| 2 |
| 1 |
| 2 |
点评:本题主要考查分数指数幂的运算法则的应用,属于基础题.
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