Question

函数y=log₂(x+1)+1(x>0)的反函数是(    )

A.y=2^x-1-1(x>1)                              B.y=2^x-1+1(x>1)

C.y=2^x-1-1(x>0)                              D.y=2^x-1+1(x>0)

Answer 1

A

解析:

由y=log₂(x+1)+1,得y-1=log₂(x+1),得x=2^y-1-1,

所以函数y=log₂(x+1)+1(x>0)的反函数是y=2^x-1-1(x>1).