ÌâÄ¿ÄÚÈÝ

Èçͼ,ijÎÛË®´¦Àí³§ÒªÔÚÒ»¸ö¾ØÐÎÎÛË®´¦Àí³Ø(ABCD)µÄ³Øµ×ˮƽÆÌÉèÎÛË®¾»»¯¹ÜµÀ(Rt∆FHE,HÊÇÖ±½Ç¶¥µã)À´´¦ÀíÎÛË®,¹ÜµÀÔ½³¤£¬ÎÛË®¾»»¯Ð§¹ûÔ½ºÃ.Éè¼ÆÒªÇó¹ÜµÀµÄ½Ó¿ÚHÊÇABµÄÖе㣬E,F·Ö±ðÂäÔÚÏß¶ÎBC,ADÉÏ.ÒÑÖªAB=20Ã×£¬AD=10Ã×£¬¼Ç¡ÏBHE=¦È.

£¨1£©ÊÔ½«ÎÛË®¾»»¯¹ÜµÀµÄ³¤¶ÈL±íʾΪ¦ÈµÄº¯Êý,²¢Ð´³ö¶¨ÒåÓò£»

£¨2£©Èôsin¦È+cos¦È=£¬Çó´Ëʱ¹ÜµÀµÄ³¤¶ÈL£»

£¨3£©ÎÊ£ºµ±¦ÈÈ¡ºÎֵʱ£¬ÎÛË®¾»»¯Ð§¹û×îºÃ£¿

²¢Çó³ö´Ëʱ¹ÜµÀµÄ³¤¶È.

 

 

 

 

¡¾´ð°¸¡¿

½â£º£¨1£©EH=£¬FH=     EF=  ·Ö

ÓÉÓÚBE=10tan¦È¡Ü10, AF=¡Ü10 ¹Ê¡Ütan¦È¡Ü,¦È¡Ê[,]·Ö

L=++£¬¦È¡Ê[,]

(2) sin¦È+cos¦È=ʱ£¬sin¦È•cos¦È=,    L=20(+1);

(3)L=++     Éèsin¦È+cos¦È=t Ôòsin¦È•cos¦È=

ÓÉÓڦȡÊ[,]£¬ËùÒÔt=sin¦È+cos¦È=sin(¦È+)¡Ê[,]

L=ÔÚ[,]ÄÚµ¥µ÷µÝ¼õ£¬

ÓÚÊǵ±t=ʱ£¬¼´¦È=,¦È=ʱLµÄ×î´óÖµ20(+1)Ã×

¡¾½âÎö¡¿ÂÔ

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø