题目内容
化简下列各式:(Ⅰ)(
| 25 |
| 9 |
| 1 |
| 2 |
| 8 |
| 125 |
| 1 |
| 3 |
| ||
| 3 |
| 27 |
| 8 |
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 2 |
(Ⅱ)
| 1 |
| 3 |
| 25 |
| 9 |
| 2 |
| 3 |
| 8 |
| 1 |
| 3 |
分析:(1)将分数指数幂转化为根式形式,即可求出结果.
(2)利用对数的运算法则,将各数的真数转化为2或3的知识幂形式,进行化简即可.
(2)利用对数的运算法则,将各数的真数转化为2或3的知识幂形式,进行化简即可.
解答:解:(1)(
)
×(
)
-(
)0÷[(
)-
+0.027-
]-
=
×
-1÷(
+
) -
=
×
-1÷(
+
)-
=
-1÷
=-
(2)
lg
+
lg
+lg(45)
=lg(
)2×
×2
×
×(
)
=lg(10×2-
+1-
×3-
+
)
=1
| 25 |
| 9 |
| 1 |
| 2 |
| 8 |
| 125 |
| 1 |
| 3 |
| ||
| 3 |
| 27 |
| 8 |
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 2 |
=
|
| 3 |
| ||
| 1 | |||||
|
| 1 | |||
|
| 1 |
| 2 |
=
| 5 |
| 3 |
| 2 |
| 5 |
| 2 |
| 3 |
| 1 |
| 0.3 |
| 1 |
| 2 |
=
| 2 |
| 3 |
| 1 | ||
|
| 4 |
| 3 |
(2)
| 1 |
| 3 |
| 25 |
| 9 |
| 2 |
| 3 |
| 8 |
| 1 |
| 3 |
=lg(
| 10 |
| 2×3 |
| 1 |
| 3 |
| 3 |
| 2 |
| 2 |
| 3 |
| 32×10 |
| 2 |
| 1 |
| 3 |
=lg(10×2-
| 2 |
| 3 |
| 1 |
| 3 |
| 2 |
| 3 |
| 2 |
| 3 |
=1
点评:本题考查指数和对数的运算法则、分数指数幂和根式的互化,考查运算能力.
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