题目内容
设函数f（x）=1n（2-3x）5，则f′(
)=______．
| 1 |
| 3 |
∵f（x）=1n（2-3x）5
∴f′（x）=
×[(2-3x)5]′
=
×5(2-3x)4×(2-3x)′
=
∴f′(
)=-15
故答案为：-15．
∴f′（x）=
| 1 |
| (2-3x)5 |
=
| 1 |
| (2-3x)5 |
=
| -15 |
| 2-3x |
∴f′(
| 1 |
| 3 |
故答案为：-15．
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