ÌâÄ¿ÄÚÈÝ

ϱí±íʾÈËÌ弡ϸ°ûÊܴ̼¤ºó£¬Ï¸°ûÄڸƺ¬Á¿ºÍ¼¡ÈâÊÕËõÁ¦Á¿ËæÊ±¼äµÄ±ä»¯¹ØÏµ£¬

Êܴ̼¤ºóʱ¼ä/ms

0

30

60

90

120

150

180

¸Æº¬Á¿/£¨mmol¡¤mL£­1£©

0

7.8

2.2

0.5

0

0

0

¼¡ÈâÊÕËõÁ¦Á¿/N

0

2.0

5

3.5

2.1

0.5

0

±íÖÐÊý¾Ý¿ÉÒÔ˵Ã÷£¨ £©

A£®Ï¸°ûÄÚ¸ÆÅ¨¶ÈÔ½¸ß¼¡ÈâÊÕËõÁ¦Á¿Ô½´ó

B£®¸ÆÔªËØÔÚѪҺÖÐÒÔ̼Ëá¸ÆµÄÐÎʽ´æÔÚ

C£®¼¡ÈâÔÚ´ïµ½×î´óÊÕËõÁ¦Ç°ÓиƵÄÊÍ·Å

D£®¼¡ÈâÊÕËõÁ¦Á¿ËæÊ±¼ä²»¶ÏÔöÇ¿

 

C

¡¾½âÎö¡¿

ÊÔÌâ·ÖÎö£ºÓɱí¸ñÊý¾Ý¿É¿´³ö£ºÔÚ¼¡ÈâÁ¦Á¿Î´´ïµ½×î´óʱ£¬¸Æº¬Á¿ÒѾ­´ïµ½×î´ó£¬µ±¼¡ÈâÁ¦Á¿´ïµ½×î´óʱ£¬¸Æº¬Á¿ÒѾ­Ï½µÁË£¬ËµÃ÷¼¡ÈâÁ¦Á¿´ïµ½×î´óǰ¸ÆÒѾ­¿ªÊ¼ÊÍ·Å£¬ËùÒÔ²¢²»ÊǸÆÀë×ÓŨ¶ÈÔ½¸ß¼¡ÈâÁ¦Á¿Ô½´ó¡£¼¡ÈâµÄÊÕËõÁ¦Á¿Óëʱ¼äÎ޹أ¬¸ÆÔªËØÔÚѪҺÖÐÒÔ¸ÆÀë×ÓµÄÐÎʽ´æÔÚ¡£

¿¼µã£º±¾Ì⿼²éÁËÎÞ»úÑÎÔÚϸ°ûÖÐ×÷ÓúÍÐÎʽÒÔ¼°Ñ§Éú·ÖÎöͼ±íµÄÄÜÁ¦¡£

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

£¨¹²14·Ö£©Å£ÄÌÖк¬Óе°°×ÖÊ¡¢Ö¬·¾¡¢Ì¼Ë®»¯ºÏÎïµÈÓªÑø³É·Ö£¬ÆäÖе°°×Öʺ¬Á¿ÊǼø±ðÅ£ÄÌÖÊÁ¿µÄÖ÷ÒªÒÀ¾Ý¡£Ä³Í¬Ñ§Óû̽¾¿Ä³Æ·ÅƵÄÅ£ÄÌÖÐÓÐÎÞµ°°×Öʺͻ¹Ô­ÌÇ¡£ÏÂÃæÊÇÆäδÉè¼ÆÍêµÄʵÑ飬Çë°ïÖúËûÍê³ÉʵÑéÉè¼Æ¡£

¡¾ÊµÑéÄ¿µÄ¡¿Ì½¾¿Ä³Æ·ÅÆÅ£ÄÌÖÐÓÐÎÞµ°°×Öʺͻ¹Ô­ÌÇ¡£

¡¾ÊµÑéÔ­Àí¡¿ÀûÓÃÑÕÉ«·´Ó¦¼ì²âÅ£ÄÌÖÐÓÐÎÞµ°°×Öʺͻ¹Ô­ÌÇ¡£

¡¾²ÄÁÏÓþߡ¿ÂÔ

¡¾ÊµÑé²½Öè¡¿Çë²¹³ä±í¸ñÖÐa¡¢b¡¢c¡¢d´¦ÄÚÈÝ£º

̽¾¿Ä¿µÄ

̽¾¿Å£ÄÌÖÐÓÐÎÞ»¹Ô­ÌÇ

̽¾¿Å£ÄÌÖÐÓÐÎÞµ°°×ÖÊ

ÊÔ¹Ü

²½Öè

A

B

C

D

E

F

µÚÒ»²½

2 mLÅ£ÄÌ

2 mL

ÕôÁóË®

2 mL

ÆÏÌÑÌÇÑùÒº

2 mL

Å£ÄÌ

2 mL

ÕôÁóË®

2 mL

__a__ÑùÒº

µÚ¶þ²½

2 mL

ì³ÁÖÊÔ¼Á

2 mL

ì³ÁÖÊÔ¼Á

2 mL

ì³ÁÖÊÔ¼Á

2 mL

NaOHÈÜÒº

__b__

2 mL

NaOHÈÜÒº

µÚÈý²½

__c__

ˮԡ¼ÓÈÈ

ˮԡ¼ÓÈÈ

__d__

3¡«4µÎ

CuSO4ÈÜÒº

3¡«4µÎ

CuSO4ÈÜÒº

½á ¹û

£¿

 

 

£¿

 

 

(1)a.________£»b.________£»c.________£»d.________¡£

(2)ÇëÔ¤²âA¡¢DÁ½¸öÊԹܵÄÏÖÏó¼°Æä½áÂÛ£º

A£º_____________________________________________________¡£

D£º_____________________________________________________¡£

(3)·ÖÎö¸ÃʵÑéÉè¼Æ£º

ÊÔ¹ÜAºÍ________¹¹³É¶ÔÕÕʵÑ飬¶ÔÕÕ×éΪ________£¬Ä¿µÄÊÇ_________________________________¡£

 

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø