ÌâÄ¿ÄÚÈÝ
ÏÖÓÐÏÂÁжÌÖÜÆÚÔªËØÐÔÖʵÄÊý¾Ý
»Ø´ðÏÂÁÐÎÊÌâ
£¨1£©ÔªËØ¢ÛÔÚÖÜÆÚ±íÖÐλÖÃÊÇ_____________£»ÔªËØ¢ÜÓëÔªËØ¢ßÏà±È½Ï£¬ÆøÌ¬Ç⻯Îï½ÏÎȶ¨µÄÊÇ
_________£¨Ìѧʽ£©£»
£¨2£©ÔªËØ¢ÙÊÇ_________£¨Ð´ÔªËØ·ûºÅ£©£¬ÔªËØ¢ÞÊÇ_________£¨Ð´ÔªËØ·ûºÅ£©£¬¶þÕß°´ÕÕÔ×Ó¸öÊý±ÈΪ1¡Ã1ÐγɵϝºÏÎïÓëË®·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ___________________________£»
£¨3£©ÔªËØ¢ÝÓëÔªËØ¢ÚµÄ·Ç½ðÊôÐÔÇ¿Èõ˳ÐòΪ_______________£¨Ð´ÔªËØ·ûºÅ£©£¬ÔªËآݵĵ¥ÖʼÓÈëµ½ÔªËØ¢ÚµÄÇ⻯ÎïµÄË®ÈÜÒºÖУ¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ__________________________£»
£¨4£©Óõç×Óʽ±íÊ¾ÔªËØ¢ÙÇ⻯ÎïµÄÐγɹý³Ì_________________________£»Ð´³öÔªËØ¢ßÇ⻯ÎïµÄµç×Óʽ
__________________£»Ð´³öʵÑéÊÒÖÆÔªËØ¢Ýµ¥ÖʵĻ¯Ñ§·´Ó¦·½³Ìʽ___________________________¡£
£¨1£©ÔªËØ¢ÛÔÚÖÜÆÚ±íÖÐλÖÃÊÇ_____________£»ÔªËØ¢ÜÓëÔªËØ¢ßÏà±È½Ï£¬ÆøÌ¬Ç⻯Îï½ÏÎȶ¨µÄÊÇ
_________£¨Ìѧʽ£©£»
£¨2£©ÔªËØ¢ÙÊÇ_________£¨Ð´ÔªËØ·ûºÅ£©£¬ÔªËØ¢ÞÊÇ_________£¨Ð´ÔªËØ·ûºÅ£©£¬¶þÕß°´ÕÕÔ×Ó¸öÊý±ÈΪ1¡Ã1ÐγɵϝºÏÎïÓëË®·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ___________________________£»
£¨3£©ÔªËØ¢ÝÓëÔªËØ¢ÚµÄ·Ç½ðÊôÐÔÇ¿Èõ˳ÐòΪ_______________£¨Ð´ÔªËØ·ûºÅ£©£¬ÔªËآݵĵ¥ÖʼÓÈëµ½ÔªËØ¢ÚµÄÇ⻯ÎïµÄË®ÈÜÒºÖУ¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ__________________________£»
£¨4£©Óõç×Óʽ±íÊ¾ÔªËØ¢ÙÇ⻯ÎïµÄÐγɹý³Ì_________________________£»Ð´³öÔªËØ¢ßÇ⻯ÎïµÄµç×Óʽ
__________________£»Ð´³öʵÑéÊÒÖÆÔªËØ¢Ýµ¥ÖʵĻ¯Ñ§·´Ó¦·½³Ìʽ___________________________¡£
£¨1£©µÚ¶þÖÜÆÚIA×壻NH3
£¨2£©O£»Na£»2Na2O2+2H2O==4NaOH+O2¡ü
£¨3£©Cl£¾S£»Cl2+H2S==2HCl+S¡ý
£¨4£©¡°ÂÔ¡±
£¨2£©O£»Na£»2Na2O2+2H2O==4NaOH+O2¡ü
£¨3£©Cl£¾S£»Cl2+H2S==2HCl+S¡ý
£¨4£©¡°ÂÔ¡±
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿