ÌâÄ¿ÄÚÈÝ

³£ÎÂÏ£¬ÏÂÁи÷ÈÜÒºµÄÐðÊöÖÐÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®0.1mol/LµÄ´×ËáÄÆÈÜÒº20mLÓë0.1mol/LÑÎËá10mL»ìºÏºóÈÜÒºÏÔËáÐÔc£¨Ac-£©£¾c£¨Cl-£©£¾c£¨H+£©£¾c£¨HAc£©
B£®pH=7µÄ´×ËáÄÆºÍ´×Ëá»ìºÏÒºÖУºc£¨Na+£©=c£¨CH3COO-£©
C£®0.1mol/LµÄ´×ËáµÄpH=a£¬0.01mol/LµÄ´×ËáµÄpH=b£¬Ôòa+1£¾b
D£®ÒÑÖªËáÐÔHF£¾CH3COOH£¬pHÏàµÈµÄNaFÓëCH3COOKÈÜÒºÖУ¬[c£¨Na+£©-c£¨F-£©]£¼[c£¨K+£©-c£¨CH3COO-£©]
A¡¢0.1mol/LµÄ´×ËáÄÆÈÜÒº20mLÓë0.1mol/LÑÎËá10mL»ìºÏºó£¬ËùµÃÈÜÒºÊǵÈŨ¶ÈµÄÂÈ»¯ÄÆ¡¢´×ËáÒÔ¼°´×ËáÄÆµÄ»ìºÏÎ¸ù¾Ý»ìºÏÒºÏÔʾËáÐÔ£¬¿ÉÒÔÈ·¶¨´×ËáµÄµçÀë³Ì¶È´óÓÚ´×Ëá¸ùÀë×ÓµÄË®½â³Ì¶È£¬Ôòc£¨Ac-£©£¾c£¨Cl-£©£¾c£¨HAc£©£¾c£¨H+£©£¬¹ÊA´íÎó£»
B¡¢´×ËáÄÆºÍ´×Ëá»ìºÏÒºÖУ¬pH=7Ôòc£¨H+£©=c£¨OH-£©£¬¸ù¾ÝµçºÉÊØºã£ºc£¨H+£©+c£¨Na+£©=c£¨CH3COO-£©+c£¨OH-£©£¬ËùÒÔ
c£¨Na+£©=c£¨CH3COO-£©£¬¹ÊBÕýÈ·£»
C¡¢0.1mol/LµÄ´×ËáµÄµçÀë¶ÈСÓÚ0.01mol/LµÄ´×ËáµÄµçÀë¶È£¬ËùÒÔa+1£¾b£¬¹ÊCÕýÈ·£»
D¡¢ËáÐÔHF£¾CH3COOH£¬NaFÓëCH3COOKÈÜÒºÖУ¬´×Ëá¸ùÀë×ÓµÄË®½â³Ì¶È´óÓÚ·úÀë×ÓµÄË®½â³Ì¶È£¬ËùÒÔ¼îÐÔ´×ËáÄÆÇ¿ÓÚ·ú»¯ÄÆ£¬ÔÚ·ú»¯ÄÆÖУ¬c£¨Na+£©-c£¨F-£©=c£¨OH-£©-c£¨H+£©£¬ÔÚ´×Ëá¼ØÖУ¬c£¨K+£©-c£¨CH3COO-£©=c£¨OH-£©-c£¨H+£©£¬pHÏàµÈµÄNaFÓëCH3COOKÈÜÒºÖУ¬ÇâÀë×ÓŨ¶ÈÏàµÈ£¬ÔòÇâÑõ¸ùŨ¶ÈÒ²ÏàµÈ£¬ËùÒÔc£¨OH-£©-c£¨H+£©ÏàµÈ£¬¼´c£¨Na+£©-c£¨F-£©]=[c£¨K+£©-c£¨CH3COO-£©£¬¹ÊD´íÎó£¬
¹ÊÑ¡BC£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø