ÌâÄ¿ÄÚÈÝ

Èâ¹ðÈ©ÊÇÒ»ÖÖʳÓÃÏ㾫£¬Ëü¹ã·ºÓÃÓÚÑÀ¸à¡¢Ï´µÓ¼Á¡¢ÌǹûÒÔ¼°µ÷ζƷÖУ®¹¤ÒµÉÏ¿Éͨ¹ýÏÂÁз´Ó¦ÖƱ¸£º

£¨1£©ÇëÍÆ²âB²àÁ´ÉÏ¿ÉÄÜ·¢Éú·´Ó¦µÄÀàÐÍ£º
 
£®£¨Ìîд´úºÅ£©   
¢Ù¼Ó³É·´Ó¦ ¢ÚÏûÈ¥·´Ó¦ ¢Ûõ¥»¯·´Ó¦ ¢Ü¾ÛºÏ·´Ó¦
£¨2£©Çëд³öÁ½·Ö×ÓÒÒÈ©ÔÚÉÏÊöÌõ¼þÏ·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º
 
£®
£¨3£©Çëд³öͬʱÂú×ãÀ¨ºÅÄÚÌõ¼þÏÂBµÄËùÓÐͬ·ÖÒì¹¹ÌåµÄ½á¹¹¼òʽ£º¢Ù·Ö×ÓÖв»º¬ôÊ»ùºÍôÇ»ù£»¢ÚÊDZ½µÄ¶Ô¶þÈ¡´úÎ¢Û³ý±½»·Í⣬²»º¬ÆäËû»·×´½á¹¹£®
 
£®
¿¼µã£ºÓлúÎïµÄ½á¹¹ºÍÐÔÖÊ
רÌ⣺ÓлúÎïµÄ»¯Ñ§ÐÔÖʼ°ÍƶÏ
·ÖÎö£º£¨1£©¸ù¾ÝB·Ö×Ó²àÁ´ÉϺ¬ÓÐ̼̼˫¼üºÍÈ©»ù¹ÙÄÜÍÅ£¬ÒÔ´Ë·ÖÎöÐÔÖÊ£»
£¨2£©ÓÉÐÅÏ¢¿ÉÖª£¬·¢Éú-CHOµÄ¼Ó³ÉºÍ-OHµÄÏûÈ¥£»
£¨3£©BµÄËùÓÐͬ·ÖÒì¹¹Ì壬·ûºÏ¢Ù·Ö×ÓÖв»º¬ôÊ»ùºÍôÇ»ù£»¢ÚÊDZ½µÄ¶Ô¶þÈ¡´úÎ¢Û³ý±½»·Í⣬²»º¬ÆäËû»·×´½á¹¹£®¼´ÔÚ±½»·µÄ¶ÔλÓÐ2¸öÈ¡´ú»ù£¬ÒÔ´Ë·ÖÎö£®
½â´ð£º ½â£º£¨1£©B·Ö×Ó²àÁ´ÉϺ¬ÓÐ̼̼˫¼üºÍÈ©»ù¹ÙÄÜÍÅ£¬º¬Ì¼Ì¼Ë«¼ü¿ÉÒÔ·¢Éú¼Ó³É·´Ó¦¡¢¼Ó¾ÛºÍÑõ»¯·´Ó¦£¬º¬È©»ù£¬¿É·¢ÉúÑõ»¯¡¢¼Ó³É¡¢»¹Ô­·´Ó¦µÈ£¬
¹Ê´ð°¸Îª£º¢Ù¢Ü£»
£¨2£©¸ù¾ÝÌâ¸ø·´Ó¦Àà±ÈÍÆ³öÁ½·Ö×ÓÒÒÈ©·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ2CH3CHO
Ï¡NaOHÈÜÒº
¡÷
CH3CH=CHCHO+H2O£¬¹Ê´ð°¸Îª£º2CH3CHO
Ï¡NaOHÈÜÒº
¡÷
CH3CH=CHCHO+H2O£»
£¨3£©BµÄËùÓÐͬ·ÖÒì¹¹Ì壬·ûºÏ¢Ù·Ö×ÓÖв»º¬ôÊ»ùºÍôÇ»ù£»¢ÚÊDZ½µÄ¶Ô¶þÈ¡´úÎ¢Û³ý±½»·Í⣬²»º¬ÆäËû»·×´½á¹¹£®·ûºÏÌõ¼þµÄͬ·ÖÒì¹¹ÌåµÄ½á¹¹¼òʽΪ£¬¹Ê´ð°¸Îª£º£®
µãÆÀ£º±¾ÌâÒÔÓлúÎïÖÆ±¸¿¼²éÓлúÎïµÄ½á¹¹ÓëÐÔÖÊ£¬Îª¸ßƵ¿¼µã£¬²àÖØÓÚѧÉúµÄ·ÖÎöÄÜÁ¦µÄ¿¼²é£¬×¢Òâ°ÑÎÕ¹ÙÄÜÍÅÓëÐÔÖʵĹØÏµ£¬±¾Ìâ²àÖØÈ©µÄÐÔÖʼ°Í¬·ÖÒì¹¹ÌåµÄ¿¼²é£¬ÌâÄ¿ÄѶȲ»´ó£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø