ÌâÄ¿ÄÚÈÝ


84Ïû¶¾Òº¡±ÄÜÓÐЧɱÃð¼×ÐÍH1N1²¡¶¾,ijͬѧ¹ºÂòÁËÒ»Æ¿Ä³Æ·ÅÆ¡°84Ïû¶¾Òº¡±,²¢²éÔÄÏà¹Ø×ÊÁϺÍÏû¶¾Òº°üװ˵Ã÷µÃµ½ÈçÏÂÐÅÏ¢:

¡°84Ïû¶¾Òº¡±:º¬25% NaClO¡¢1 000 mL¡¢ÃܶÈ1.19 g¡¤cm-3,Ï¡ÊÍ100±¶(Ìå»ý±È)ºóʹÓá£

Çë¸ù¾ÝÒÔÉÏÐÅÏ¢ºÍÏà¹ØÖªÊ¶»Ø´ðÏÂÁÐÎÊÌâ:

(1)¸Ã¡°84Ïû¶¾Òº¡±µÄÎïÖʵÄÁ¿Å¨¶ÈΪ¡¡¡¡¡¡¡¡mol¡¤L-1¡£

(2)¸Ãͬѧȡ100 mL¸ÃÆ·ÅÆ¡°84Ïû¶¾Òº¡±Ï¡ÊͺóÓÃÓÚÏû¶¾,Ï¡ÊͺóµÄÈÜÒºÖÐc(Na+)¡Ö¡¡¡¡¡¡¡¡mol¡¤L-1(¼ÙÉèÏ¡ÊͺóÈÜÒºÃܶÈΪ1.0 g¡¤cm-3)¡£

(3)¸Ãͬѧ²ÎÔÄ¸ÃÆ·ÅÆ¡°84Ïû¶¾Òº¡±µÄÅä·½,ÓûÓÃNaClO¹ÌÌåÅäÖÆ480 mLº¬25% NaClOµÄÏû¶¾Òº¡£ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ¡¡¡¡¡¡¡¡¡£

A.Ñ¡ÓÃ480 mLµÄÈÝÁ¿Æ¿

B.ÈÝÁ¿Æ¿ÓÃÕôÁóˮϴ¾»ºó,Ó¦ºæ¸É²ÅÄÜÓÃÓÚÈÜÒºÅäÖÆ

C.ÀûÓùºÂòµÄÉÌÆ·NaClOÀ´ÅäÖÆ¿ÉÄܵ¼Ö½á¹ûÆ«µÍ

D.ÐèÒª³ÆÁ¿µÄNaClO¹ÌÌåÖÊÁ¿Îª143 g


¡¾½âÎö¡¿(1)¸ù¾Ý

(2)4.0 mol¡¤L-1µÄNaClOÈÜҺϡÊÍ100±¶ºó,ÆäŨ¶ÈΪ0.04 mol¡¤L-1,¼´c(Na+)=0.04 mol¡¤L-1¡£

(3)Ñ¡ÏîA,ʵÑéÊÒûÓÐ480 mLµÄÈÝÁ¿Æ¿,ӦѡÓÃ500 mLµÄÈÝÁ¿Æ¿;Ñ¡ÏîB,ÅäÖÆ¹ý³ÌÖÐÐèÒª¼ÓÈëË®,ËùÒÔ¾­Ï´µÓ¸É¾»µÄÈÝÁ¿Æ¿²»±Øºæ¸ÉºóÔÙʹÓÃ;Ñ¡ÏîC,ÓÉÓÚNaClOÒ×ÎüÊÕ¿ÕÆøÖеÄH2O¡¢CO2¶ø±äÖÊ,ËùÒÔÉÌÆ·NaClO¿ÉÄܲ¿·Ö±äÖʵ¼ÖÂNaClO¼õÉÙ,ÅäÖÆµÄÈÜÒºÖÐÈÜÖʵÄÎïÖʵÄÁ¿¼õС,½á¹ûÆ«µÍ;Ñ¡ÏîD,ѡȡ500 mLµÄÈÝÁ¿Æ¿½øÐÐÅäÖÆ,±ØÐë°´500 mLÈÜÒº¼ÆËãËùÐèÈÜÖʵÄÁ¿,ËùÒÔÐèÒªNaClOµÄÖÊÁ¿Îª

0.5 L¡Á4.0 mol¡¤L-1¡Á74.5 g¡¤mol-1=149 g¡£

´ð°¸:(1)4.0           (2)0.04             (3)C


Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø