ÌâÄ¿ÄÚÈÝ
п¼°Æä»¯ºÏÎïÓÃ;¹ã·º¡£»ð·¨Á¶Ð¿ÒÔÉÁп¿ó£¨Ö÷Òª³É·ÖÊÇZnS£©ÎªÖ÷ÒªÔÁÏ£¬Éæ¼°µÄÖ÷Òª·´Ó¦ÓУº
2ZnS(s) + 3O2(g) = 2ZnO(s) + 2SO2(g)
H1=£930 kJ¡¤mol£1
2C(s) + O2(g) = 2CO(g)
H2=£221 kJ¡¤mol£1
ZnO(s) + CO(g) = Zn(g) + CO2(g)
H3=198 kJ¡¤mol£1
·´Ó¦ZnS(s) + C(s) + 2O2(g)£½Zn(g) + CO2(g) + SO2(g)
µÄ
H4= kJ¡¤mol£1¡£
£¨2£©·´Ó¦ÖÐÉú³ÉµÄCO2ÓëNH3»ìºÏ£¬ÔÚÒ»¶¨Ìõ¼þÏ·´Ó¦ºÏ³ÉÄòËØ£º
2NH3£¨g£©+CO2£¨g£©
CO£¨NH2£©2£¨s£©+H2O£¨g£©¡÷H©‚0
Èô¸Ã·´Ó¦ÔÚÒ»ºãΡ¢ºãÈÝÃܱÕÈÝÆ÷ÄÚ½øÐУ¬ÅжϷ´Ó¦´ïµ½Æ½ºâ״̬µÄ±êÖ¾ÊÇ ¡£
a£®CO2ÓëH2O(g)Ũ¶ÈÏàµÈ b£®ÈÝÆ÷ÖÐÆøÌåµÄѹǿ²»Ôٸıä
c£®2v(NH3)Õý = v(H2O)Äæ d£®ÈÝÆ÷ÖлìºÏÆøÌåµÄÃܶȲ»Ôٸıä
ÈôÏëÌá¸ß°±ÆøµÄת»¯ÂÊ£¬¿ÉÒÔ²ÉÈ¡µÄ´ëÊ©ÓÐ £¨Ð´³öÁ½Ìõ£©
£¨3£©ÁòËáп¿É¹ã·ºÓÃ×÷ӡȾýȾ¼ÁºÍľ²Ä·À¸¯¼Á¡£ZnSO4ÊÜÈÈ·Ö½â¹ý³ÌÖи÷ÎïÖÊÎïÖʵÄÁ¿ËæÎ¶ȱ仯¹ØÏµÈçͼËùʾ¡£
¢Ù700¡æ¡«980¡æÊ±·¢Éú·´Ó¦ÖÐÉú³ÉÎïÖʶþÑõ»¯Áò¡¢ZnOºÍÑõÆø£¬Èç¸Ã·´Ó¦ÔÚ2LÃܱÕÈÝÆ÷ÄÚ½øÐУ¬10minʱ£¬²âµÃÉú³ÉµÄÑõÆøµÄÎïÖʵÄÁ¿Îª0.3mol£¬ÔòÕâ¶Îʱ¼ä¶þÑõ»¯ÁòµÄÉú³ÉËÙÂÊΪ ¡£
¢Ú ÁòËáп·Ö½âÉú³ÉµÄSO2¾ÏÂͼÖеÄÑ»·¿ÉµÃµ½H2SO4¡£Ñ»·Öеç½â¹ý³ÌÑô¼«·´Ó¦Ê½ÊÇ ¡£
![]()
![]()
ijͬѧÔÚÓÃÏ¡ÁòËáÓëÐ¿ÖÆÈ¡ÇâÆøµÄʵÑéÖУ¬·¢ÏÖ¼ÓÈëÉÙÁ¿ÁòËáÍÈÜÒº¿É¼Ó¿ìÇâÆøµÄÉú³ÉËÙÂÊ¡£Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÁòËáÍÈÜÒº¿ÉÒÔ¼Ó¿ìÇâÆøÉú³ÉËÙÂʵÄÔÒòÊÇ_________£»
£¨2£©ÊµÑéÊÒÖÐÏÖÓÐNa2SO4¡¢MgSO4¡¢HgSO4¡¢K2SO4µÈ4ÖÖÈÜÒº£¬¿ÉÓëʵÑéÖÐCuSO4ÈÜÒºÆðÏàËÆ×÷ÓõÄÊÇ__________£»
£¨3£©ÎªÁ˽øÒ»²½Ñо¿ÁòËá͵ÄÁ¿¶ÔÇâÆøÉú³ÉËÙÂʵÄÓ°Ï죬¸ÃͬѧÉè¼ÆÁËÈçÏÂһϵÁÐʵÑé¡£½«±íÖÐËù¸øµÄ»ìºÏÈÜÒº·Ö±ð¼ÓÈëµ½6¸öÊ¢ÓйýÁ¿ZnÁ£µÄ·´Ó¦Æ¿ÖУ¬ÊÕ¼¯²úÉúµÄÆøÌ壬¼Ç¼»ñµÃÏàͬÌå»ýµÄÆøÌåËùÐèʱ¼ä¡£
ʵÑé »ìºÏÈÜÒº | A | B | C | D | E | F |
4mol¡¤L-1H2SO4ÈÜÒº/mL | 30 | V1 | V2 | V3 | V4 | V5 |
±¥ºÍCuSO4ÈÜÒº/mL | 0 | 0.5 | 2.5 | 5 | V6 | 20 |
H2O/mL | V7 | V8 | V9 | V10 | 10 | 0 |
¢ÙÇëÍê³É´ËʵÑéÉè¼Æ£¬ÆäÖУºV1=______mL£¬V9=_____mL£»
¢Ú¸Ãͬѧ×îºóµÃ³öµÄ½áÂÛΪ£ºµ±¼ÓÈëÉÙÁ¿CuSO4ÈÜҺʱ£¬Éú³ÉÇâÆøµÄËÙÂÊ»á´ó´óÌá¸ß£¬µ«µ±¼ÓÈëµÄCuSO4ÈÜÒº³¬¹ýÒ»¶¨Á¿Ê±£¬Éú³ÉÇâÆøµÄËÙÂÊ·´¶ø»áϽµ¡£Çë·ÖÎöÇâÆøÉú³ÉËÙÂÊϽµµÄÖ÷ÒªÔÒò_____________________________¡£