ÌâÄ¿ÄÚÈÝ

Á×ÔÚÑõÆøÖÐȼÉÕ£¬¿ÉÄÜÉú³ÉÁ½ÖÖ¹Ì̬Ñõ»¯Î3.1gµÄµ¥ÖÊÁ×£¨P£©ÔÚ3.2gµÄÑõÆøÖÐȼÉÕ£¬ÖÁ·´Ó¦ÎïºÄ¾¡£¬²¢·Å³öXkJÈÈÁ¿£®
£¨1£©Í¨¹ý¼ÆËãÈ·¶¨·´Ó¦²úÎïµÄ×é³É£¨Óû¯Ñ§Ê½±íʾ£©ÊÇ______£¬ÆäÏàÓ¦ÖÊÁ¿£¨g£©Îª______£®
£¨2£©ÒÑÖªµ¥ÖÊÁ×µÄȼÉÕÈÈΪYkJ/mol£¬Ôò1mol PÓëO2·´Ó¦Éú³É¹Ì̬P2O3µÄ·´Ó¦ÈÈ¡÷H=______£®
£¨3£©Ð´³ö1molPÓëO2·´Ó¦Éú³É¹Ì̬P2O3µÄÈÈ»¯Ñ§·½³Ìʽ£º______£®
£¨1£©3.1gµÄµ¥ÖÊÁ×£¨P£©µÄÎïÖʵÄÁ¿Îª
3.1g
31g/mol
=0.1mol£¬3.2gµÄÑõÆøµÄÎïÖʵÄÁ¿Îª
3.2g
32g/mol
=0.1mol£¬¹ÊPÔ­×ÓÓëOÔ­×ÓµÄÊýĿ֮±ÈΪ0.1mol£º0.1mol¡Á2=1£º2£¬2£º5£¼1£º2£¼2£º3£¬¹Ê·´Ó¦²úÎïΪP2O3¡¢P2O5£¬ÁîÎïÖʵÄÁ¿·Ö±ðΪxmol¡¢ymol£¬Ôò£º
2x+2y=0.1
3x+5y=0.1¡Á2

½âµÃ£ºx=0.025mol£¬y=0.025mol
¹ÊP2O3µÄÖÊÁ¿Îª0.025mol¡Á110g/mol=2.75g£¬
P2O5µÄÖÊÁ¿Îª0.025mol¡Á142g/mol=3.55g£¬
¹Ê´ð°¸Îª£ºP2O3¡¢P2O5£¬2.75g¡¢3.55g£»
£¨2£©µ¥ÖÊÁ×µÄȼÉÕÈÈΪYkJ/mol£¬¼´1molÁ×ÍêȫȼÉÕÉú³É¹Ì̬P2O5·Å³öµÄÈÈÁ¿ÎªYkJ£¬·´Ó¦ÖÐÉú³É0.025molP2O5£¬ÐèÒªÁ×0.05mol£¬¹Ê0.05molÁ×ȼÉÕÉú³ÉÉú³É¹Ì̬P2O5·Å³öµÄÈÈÁ¿Îª0.05YkJ£¬·´Ó¦ÖÐÉú³É0.025molP2O3£¬ÐèÒªÁ×0.05mol£¬¹Ê
ËùÒÔ0.05molÁ×ȼÉÕÉú³ÉÉú³É¹Ì̬P2O3·Å³öµÄÈÈÁ¿ÎªXkJ-0.05YkJ=£¨X-0.05Y£©kJ£¬ËùÒÔ1molPÓëO2·´Ó¦Éú³É¹Ì̬P2O3·Å³öµÄÈÈÁ¿Îª£¨X-0.05Y£©kJ¡Á
1mol
0.05mol
=£¨20X-Y£©kJ£¬¹Ê1mol PÓëO2·´Ó¦Éú³É¹Ì̬P2O3µÄ·´Ó¦ÈÈ¡÷H=-£¨20X-Y£©kJ/mol£¬
¹Ê´ð°¸Îª£º-£¨20X-Y£©kJ/mol£»
£¨3£©ÓÉ£¨2£©¿ÉÖª£¬1molPÓëO2·´Ó¦Éú³É¹Ì̬P2O3µÄÈÈ»¯Ñ§·½³Ìʽ£ºP£¨s£©+
3
4
O2£¨g£©=
1
2
P2O3£¨s£©¡÷H=-£¨20X-Y£©kJ/mol£¬
¹Ê´ð°¸Îª£ºP£¨s£©+
3
4
O2£¨g£©=
1
2
P2O3£¨s£©¡÷H=-£¨20X-Y£©kJ/mol£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø