ÌâÄ¿ÄÚÈÝ

£¨8·Ö£©ÊµÑéÊÒÓмס¢ÒÒÁ½Æ¿ÎÞÉ«ÈÜÒº£¬ÆäÖÐһƿÊÇÏ¡ÑÎËᣬÁíһƿÊÇ̼ËáÄÆÈÜÒº¡£Îª²â¶¨¼×¡¢ÒÒÁ½Æ¿ÈÜÒºµÄ³É·Ö¼°ÎïÖʵÄÁ¿Å¨¶È£¬½øÐÐÒÔÏÂʵÑ飺

¢ÙÈ¡25mL¼×ÈÜÒº£¬ÏòÆäÖлºÂýµÎÈëÒÒÈÜÒº15mL£¬¹²ÊÕ¼¯µ½112mL£¨±ê×¼×´¿ö£©ÆøÌå¡£

¢ÚÈ¡15mLÒÒÈÜÒº£¬ÏòÆäÖлºÂýµÎÈë¼×ÈÜÒº25mL£¬¹²ÊÕ¼¯µ½56mL£¨±ê×¼×´¿ö£©ÆøÌå¡£

   £¨1£©Åжϣº¼×ÊÇ            ÈÜÒº£¬ÒÒÊÇ            ÈÜÒº£»£¨¾ùÌѧʽ£©

£¨2£©¼×ÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶ÈΪ       mol/L£¬ÒÒÈÜÒºµÄÎïÖʵÄÁ¿Å¨¶È

Ϊ       mol/L£¬  £¨ÒªÇóд³ö¼ÆËã¹ý³Ì£©¡£

 

£¨1£©HCl£¨1·Ö£© Na2CO3£¨1·Ö£©

   £¨2£©0.4£¨3·Ö£©       0.5£¨3·Ö£©

½âÎö:ÂÔ

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø