ÌâÄ¿ÄÚÈÝ
(1)¼×´¼ÊÇÒ»ÖÖÖØÒªµÄ»¯¹¤²úÆ·£¬¿ÉÀûÓü״¼´ß»¯ÍÑÇâÖÆ±¸¼×È©¡£¼×È©ÓëÆøÌ¬¼×´¼×ª»¯µÄÄÜÁ¿¹ØÏµÈçͼËùʾ¡£

·´Ó¦¹ý³ÌÖеÄÄÜÁ¿¹ØÏµ
¢Ù¼×´¼´ß»¯ÍÑÇâת»¯Îª¼×È©µÄ·´Ó¦ÊÇ________(Ìî¡°ÎüÈÈ¡±»ò¡°·ÅÈÈ¡±)·´Ó¦¡£
¢Ú¹ý³Ì¢ñÓë¹ý³Ì¢òµÄ·´Ó¦ÈÈÊÇ·ñÏàͬ£¿____________ÔÒòÊÇ____________ ______________________________¡£
¢Ûд³ö¼×´¼´ß»¯ÍÑÇâת»¯Îª¼×È©µÄÈÈ»¯Ñ§·´Ó¦·½³Ìʽ______________ _____________________¡£
(2)ÒÑÖª£º¢ÙCH3OH(g)£«H2O(g)=CO2(g)£«3H2(g)¡¡¦¤H£½£«49.0 kJ¡¤mol£1
¢ÚCH3OH(g)£«
O2(g)=CO2(g)£«2H2(g)¡¡¦¤H£½£192.9 kJ¡¤mol£1
ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ________¡£

·´Ó¦¹ý³ÌÖеÄÄÜÁ¿¹ØÏµ
¢Ù¼×´¼´ß»¯ÍÑÇâת»¯Îª¼×È©µÄ·´Ó¦ÊÇ________(Ìî¡°ÎüÈÈ¡±»ò¡°·ÅÈÈ¡±)·´Ó¦¡£
¢Ú¹ý³Ì¢ñÓë¹ý³Ì¢òµÄ·´Ó¦ÈÈÊÇ·ñÏàͬ£¿____________ÔÒòÊÇ____________ ______________________________¡£
¢Ûд³ö¼×´¼´ß»¯ÍÑÇâת»¯Îª¼×È©µÄÈÈ»¯Ñ§·´Ó¦·½³Ìʽ______________ _____________________¡£
(2)ÒÑÖª£º¢ÙCH3OH(g)£«H2O(g)=CO2(g)£«3H2(g)¡¡¦¤H£½£«49.0 kJ¡¤mol£1
¢ÚCH3OH(g)£«
ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ________¡£
| A£®CH3OHת±ä³ÉH2µÄ¹ý³ÌÒ»¶¨ÒªÎüÊÕÄÜÁ¿ |
| B£®¢Ù·´Ó¦ÖУ¬·´Ó¦ÎïµÄ×ÜÄÜÁ¿¸ßÓÚÉú³ÉÎïµÄ×ÜÄÜÁ¿ |
| C£®¸ù¾Ý¢ÚÍÆÖª·´Ó¦£ºCH3OH(l)£« |
| D£®·´Ó¦¢ÚµÄÄÜÁ¿±ä»¯ÈçͼËùʾ |
(1)¢ÙÎüÈÈ¡¡¢ÚÏàͬ¡¡Ò»¸ö»¯Ñ§·´Ó¦µÄ·´Ó¦ÈȽöÓ뷴Ӧʼ̬ºÍÖÕ̬Óйأ¬¶øÓë·´Ó¦µÄ;¾¶Î޹ء¡¢ÛCH3OH(g)
HCHO(g)£«H2(g)¡¡¦¤H£½£«(E2£E1)kJ¡¤mol£1¡¡(2)C
(1)¢ÙE1£¼E2£¬¼×´¼´ß»¯ÍÑÇâת»¯Îª¼×È©µÄ·´Ó¦ÊÇÎüÈÈ·´Ó¦¡£¢Ú·´Ó¦ÈÈÓë·´Ó¦µÄʼ̬ºÍÖÕ̬Óйأ¬Óë·´Ó¦µÄ;¾¶Î޹أ¬¹Ê·´Ó¦ÈÈÏàͬ¡£
(2)²ÉÓ÷´Ó¦¢Ù½«CH3OHת±ä³ÉH2ʱ£¬·´Ó¦ÎüÈÈ£¬²ÉÓ÷´Ó¦¢Ú½«CH3OHת±ä³ÉH2ʱ£¬·´Ó¦·ÅÈÈ£¬A´íÎó£»·´Ó¦ÎïµÄ×ÜÄÜÁ¿Ð¡ÓÚÉú³ÉÎïµÄ×ÜÄÜÁ¿Ê±£¬·´Ó¦ÎüÈÈ£¬B´íÎó£»ÒºÌ¬¼×´¼×ª±ä³ÉÆøÌ¬¼×´¼Ê±£¬ÒªÎüÊÕÈÈÁ¿£¬ÒºÌ¬¼×´¼²ÎÓ뷴Ӧʱ£¬·Å³öµÄÈÈÁ¿±ÈÆøÌ¬¼×´¼µÄÉÙ£¬¦¤H±ä´ó£¬CÕýÈ·£»·´Ó¦¢Ú·ÅÈÈ£¬1 mol CH3OH(g)ºÍ
mol O2(g)µÄ×ÜÄÜÁ¿´óÓÚ1 mol CO2(g)ºÍ2 mol H2(g)µÄ×ÜÄÜÁ¿£¬Óëͼʾ²»·û£¬D´íÎó¡£
(2)²ÉÓ÷´Ó¦¢Ù½«CH3OHת±ä³ÉH2ʱ£¬·´Ó¦ÎüÈÈ£¬²ÉÓ÷´Ó¦¢Ú½«CH3OHת±ä³ÉH2ʱ£¬·´Ó¦·ÅÈÈ£¬A´íÎó£»·´Ó¦ÎïµÄ×ÜÄÜÁ¿Ð¡ÓÚÉú³ÉÎïµÄ×ÜÄÜÁ¿Ê±£¬·´Ó¦ÎüÈÈ£¬B´íÎó£»ÒºÌ¬¼×´¼×ª±ä³ÉÆøÌ¬¼×´¼Ê±£¬ÒªÎüÊÕÈÈÁ¿£¬ÒºÌ¬¼×´¼²ÎÓ뷴Ӧʱ£¬·Å³öµÄÈÈÁ¿±ÈÆøÌ¬¼×´¼µÄÉÙ£¬¦¤H±ä´ó£¬CÕýÈ·£»·´Ó¦¢Ú·ÅÈÈ£¬1 mol CH3OH(g)ºÍ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿