ÌâÄ¿ÄÚÈÝ

(1)¼×´¼ÊÇÒ»ÖÖÖØÒªµÄ»¯¹¤²úÆ·£¬¿ÉÀûÓü״¼´ß»¯ÍÑÇâÖÆ±¸¼×È©¡£¼×È©ÓëÆøÌ¬¼×´¼×ª»¯µÄÄÜÁ¿¹ØÏµÈçͼËùʾ¡£

·´Ó¦¹ý³ÌÖеÄÄÜÁ¿¹ØÏµ
¢Ù¼×´¼´ß»¯ÍÑÇâת»¯Îª¼×È©µÄ·´Ó¦ÊÇ________(Ìî¡°ÎüÈÈ¡±»ò¡°·ÅÈÈ¡±)·´Ó¦¡£
¢Ú¹ý³Ì¢ñÓë¹ý³Ì¢òµÄ·´Ó¦ÈÈÊÇ·ñÏàͬ£¿____________Ô­ÒòÊÇ____________ ______________________________¡£
¢Ûд³ö¼×´¼´ß»¯ÍÑÇâת»¯Îª¼×È©µÄÈÈ»¯Ñ§·´Ó¦·½³Ìʽ______________ _____________________¡£
(2)ÒÑÖª£º¢ÙCH3OH(g)£«H2O(g)=CO2(g)£«3H2(g)¡¡¦¤H£½£«49.0 kJ¡¤mol£­1
¢ÚCH3OH(g)£« O2(g)=CO2(g)£«2H2(g)¡¡¦¤H£½£­192.9 kJ¡¤mol£­1
ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ________¡£
A£®CH3OHת±ä³ÉH2µÄ¹ý³ÌÒ»¶¨ÒªÎüÊÕÄÜÁ¿
B£®¢Ù·´Ó¦ÖУ¬·´Ó¦ÎïµÄ×ÜÄÜÁ¿¸ßÓÚÉú³ÉÎïµÄ×ÜÄÜÁ¿
C£®¸ù¾Ý¢ÚÍÆÖª·´Ó¦£ºCH3OH(l)£«O2(g)=CO2(g)£«2H2(g)µÄ¦¤H£¾£­192.9 kJ¡¤mol£­1
D£®·´Ó¦¢ÚµÄÄÜÁ¿±ä»¯ÈçͼËùʾ
(1)¢ÙÎüÈÈ¡¡¢ÚÏàͬ¡¡Ò»¸ö»¯Ñ§·´Ó¦µÄ·´Ó¦ÈȽöÓ뷴Ӧʼ̬ºÍÖÕ̬Óйأ¬¶øÓë·´Ó¦µÄ;¾¶Î޹ء¡¢ÛCH3OH(g) HCHO(g)£«H2(g)¡¡¦¤H£½£«(E2£­E1)kJ¡¤mol£­1¡¡(2)C
(1)¢ÙE1£¼E2£¬¼×´¼´ß»¯ÍÑÇâת»¯Îª¼×È©µÄ·´Ó¦ÊÇÎüÈÈ·´Ó¦¡£¢Ú·´Ó¦ÈÈÓë·´Ó¦µÄʼ̬ºÍÖÕ̬Óйأ¬Óë·´Ó¦µÄ;¾¶Î޹أ¬¹Ê·´Ó¦ÈÈÏàͬ¡£
(2)²ÉÓ÷´Ó¦¢Ù½«CH3OHת±ä³ÉH2ʱ£¬·´Ó¦ÎüÈÈ£¬²ÉÓ÷´Ó¦¢Ú½«CH3OHת±ä³ÉH2ʱ£¬·´Ó¦·ÅÈÈ£¬A´íÎó£»·´Ó¦ÎïµÄ×ÜÄÜÁ¿Ð¡ÓÚÉú³ÉÎïµÄ×ÜÄÜÁ¿Ê±£¬·´Ó¦ÎüÈÈ£¬B´íÎó£»ÒºÌ¬¼×´¼×ª±ä³ÉÆøÌ¬¼×´¼Ê±£¬ÒªÎüÊÕÈÈÁ¿£¬ÒºÌ¬¼×´¼²ÎÓ뷴Ӧʱ£¬·Å³öµÄÈÈÁ¿±ÈÆøÌ¬¼×´¼µÄÉÙ£¬¦¤H±ä´ó£¬CÕýÈ·£»·´Ó¦¢Ú·ÅÈÈ£¬1 mol CH3OH(g)ºÍ mol O2(g)µÄ×ÜÄÜÁ¿´óÓÚ1 mol CO2(g)ºÍ2 mol H2(g)µÄ×ÜÄÜÁ¿£¬Óëͼʾ²»·û£¬D´íÎó¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
½«Ãº×ª»¯ÎªË®ÃºÆøµÄÖ÷Òª»¯Ñ§·´Ó¦ÎªC(s)£«H2O(g) CO(g)£«H2(g)£»C(s)¡¢CO(g)ºÍH2(g)ÍêȫȼÉÕµÄÈÈ»¯Ñ§·½³ÌʽΪ£º
C(s)£«O2(g)=CO2(g)¡¡¦¤H£½£­393.5 kJ¡¤mol£­1
H2(g)£« O2(g)=H2O(g)¡¡¦¤H£½£­242.0 kJ¡¤mol£­1
CO(g)£«O2(g)=CO2(g)¡¡¦¤H£½£­283.0 kJ¡¤mol£­1
Çë»Ø´ð£º
(1)¸ù¾ÝÒÔÉÏÊý¾Ý£¬Ð´³öC(s)ÓëË®ÕôÆø·´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ£º________¡£
(2)±È½Ï·´Ó¦ÈÈÊý¾Ý¿ÉÖª£¬1 mol CO(g)ºÍ1 mol H2(g)ÍêȫȼÉշųöµÄÈÈÁ¿Ö®ºÍ±È1 mol C(s)ÍêȫȼÉշųöµÄÈÈÁ¿¶à¡£¼×ͬѧ¾Ý´ËÈÏΪ¡°Ãº×ª»¯ÎªË®ÃºÆø¿ÉÒÔʹúȼÉշųö¸ü¶àµÄÈÈÁ¿¡±£»ÒÒͬѧ¸ù¾Ý¸Ç˹¶¨ÂÉ×÷³öÏÂÁÐÑ­»·Í¼£º

²¢¾Ý´ËÈÏΪ¡°Ãº×ª»¯ÎªË®ÃºÆøÔÙȼÉշųöµÄÈÈÁ¿Óëúֱ½ÓȼÉշųöµÄÈÈÁ¿ÏàµÈ¡±¡£
Çë·ÖÎö£º¼×¡¢ÒÒÁ½Í¬Ñ§¹ÛµãÕýÈ·µÄÊÇ________(Ìî¡°¼×¡±»ò¡°ÒÒ¡±)£»ÅжϵÄÀíÓÉÊÇ________¡£
(3)½«Ãº×ª»¯ÎªË®ÃºÆø×÷ΪȼÁϺÍúֱ½ÓȼÉÕÏà±ÈÓкܶàÓŵ㣬ÇëÁÐ¾ÙÆäÖеÄÁ½¸öÓŵã________¡£
(4)Ë®ÃºÆø²»½öÊÇÓÅÁ¼µÄÆøÌåȼÁÏ£¬Ò²ÊÇÖØÒªµÄÓлú»¯¹¤Ô­ÁÏ¡£COºÍH2ÔÚÒ»¶¨Ìõ¼þÏ¿ÉÒԺϳɣº¢Ù¼×´¼£»¢Ú¼×È©£»¢Û¼×Ë᣻¢ÜÒÒËá¡£ÊÔ·ÖÎöµ±COºÍH2°´1£º1µÄÌå»ý±È»ìºÏ·´Ó¦£¬ºÏ³ÉÉÏÊö________(ÌîÐòºÅ)ÎïÖÊʱ£¬¿ÉÒÔÂú×ã¡°ÂÌÉ«»¯Ñ§¡±µÄÒªÇó£¬ÍêÈ«ÀûÓÃÔ­ÁÏÖеÄÔ­×Ó£¬ÊµÏÖÁãÅÅ·Å¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø