ÌâÄ¿ÄÚÈÝ


ÒÑÖªA¡¢B¡¢C¡¢D¡¢E¡¢FÊǺ¬ÓÐͬһÖÖÔªËØµÄ»¯ºÏÎÆäÖÐFÊÇÄÜʹºìɫʪÈóʯÈïÊÔÖ½±äÀ¶µÄÆøÌ壬ËüÃÇÖ®¼äÄÜ·¢ÉúÈçÏ·´Ó¦

¢ÙA£«H2O¡úB£«C¡¡¢ÚC£«F¡úD

¢ÛD£«NaOHF£«E£«H2O

(1)д³öËüÃǵĻ¯Ñ§Ê½£ºC__________¡¢D__________¡¢E________¡£

(2)д³ö¸÷²½·´Ó¦µÄÀë×Ó·½³Ìʽ

¢Ù________________________________________________________________________£¬

¢Û________________________________________________________________________¡£

(3)¹¤ÒµÉú²úCµÄ¹ý³ÌÖÐÓÐÈçÏÂÒ»²½·´Ó¦£¬¼´F¾­´ß»¯Ñõ»¯Éú³ÉBºÍH2O£¬Ð´³ö¸Ã²½·´Ó¦µÄ»¯Ñ§·½³Ìʽ

________________________________________________________________________¡£


(1)HNO3¡¡NH4NO3¡¡NaNO3

(2)¢Ù3NO2£«H2O===2H£«£«2NO£«NO

¢ÛNH£«OH£­NH3¡ü£«H2O

(3)4NH3£«5O24NO£«6H2O


Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

I£®½«Ò»¶¨Á¿NO2ºÍN2O4µÄ»ìºÏÆøÌåͨÈëÌå»ýΪ1LµÄºãÎÂÃܱÕÈÝÆ÷ÖУ¬¸÷Îï

ÖÊŨ¶ÈËæÊ±¼ä±ä»¯µÄ¹ØÏµÈçͼ1Ëùʾ¡£

 

Çë»Ø´ð£º

£¨1£©ÏÂÁÐÑ¡ÏîÖв»ÄÜ˵Ã÷¸Ã·´Ó¦ÒѴﵽƽºâ״̬µÄÊÇ            £¨ÌîÑ¡Ïî×Öĸ£©¡£

    A£®ÈÝÆ÷ÄÚ»ìºÏÆøÌåµÄѹǿ²»ËæÊ±¼ä±ä»¯¶ø¸Ä±ä

    B£®ÈÝÆ÷ÄÚ»ìºÏÆøÌåµÄÃܶȲ»ËæÊ±¼ä±ä»¯¶ø¸Ä±ä

    C£®ÈÝÆ÷ÄÚ»ìºÏÆøÌåµÄÑÕÉ«²»ËæÊ±¼ä±ä»¯¶ø¸Ä±ä

    D£®ÈÝÆ÷ÄÚ»ìºÏÆøÌåµÄƽ¾ùÏà¶Ô·Ö×ÓÖÊÁ¿²»ËæÊ±¼ä±ä»¯¶ø¸Ä±ä

£¨2£©·´Ó¦½øÐе½10 minʱ£¬¹²ÎüÊÕÈÈÁ¿11£®38 kJ£¬Ôò¸Ã·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽΪ

                                                                      £»

£¨3£©¼ÆËã¸Ã·´Ó¦µÄƽºâ³£ÊýK=                                           ¡£

£¨4£©·´Ó¦½øÐе½20 minʱ£¬ÔÙÏòÈÝÆ÷ÄÚ³äÈëÒ»¶¨Á¿NO2£¬10minºó´ïµ½ÐÂµÄÆ½ºâ£¬´Ëʱ²âµÃc£¨NO2£©=0£®9 mol£¯L¡£

¢ÙµÚÒ»´Îƽºâʱ»ìºÏÆøÌåÖÐNO2µÄÌå»ý·ÖÊýΪw1£¬´ïµ½ÐÂÆ½ºâºó»ìºÏÆøÌåÖÐNO2µÄÌå»ý·ÖÊýΪw2£¬Ôòw1               w2 £¨Ìî¡°>¡±¡¢¡°=¡±»ò¡°<¡±£©£»

¢ÚÇëÔÚͼ2Öл­³ö20 minºó¸÷ÎïÖʵÄŨ¶ÈËæÊ±¼ä±ä»¯µÄÇúÏߣ¨ÇúÏßÉϱØÐë±ê³ö¡°X¡±ºÍ¡°Y¡±£©¡£

II£®£¨1£©º£Ë®ÖÐï®ÔªËØ´¢Á¿·Ç³£·á¸»£¬´Óº£Ë®ÖÐÌáȡ﮵ÄÑо¿¼«¾ßDZÁ¦¡£ï®ÊÇÖÆÔ컯ѧµçÔ´µÄÖØÒªÔ­ÁÏ¡£ÈçLiFePO4µç³ØÖÐijµç¼«µÄ¹¤×÷Ô­ÀíÈçÏÂͼËùʾ£º

 

¸Ãµç³ØµÄµç½âÖÊΪÄÜ´«µ¼Li+µÄ¹ÌÌå²ÄÁÏ¡£·Åµçʱ¸Ãµç¼«ÊÇµç³ØµÄ               ¼«£¨Ìî¡°Õý¡±»ò¡°¸º¡±£©£¬¸Ãµç¼«·´Ó¦Ê½Îª                                       ¡£

£¨2£©ÓÃ´Ëµç³Øµç½âº¬ÓÐ0£®1 mol/L CuSO4ºÍ0£®1 mol/L NaClµÄ»ìºÏÈÜÒº100 mL£¬¼ÙÈçµç·ÖÐ×ªÒÆÁË0£®02 mol e£­£¬ÇÒµç½â³ØµÄµç¼«¾ùΪ¶èÐԵ缫£¬Ñô¼«²úÉúµÄÆøÌåÔÚ±ê×¼×´¿öϵÄÌå»ýÊÇ__________L£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø