ÌâÄ¿ÄÚÈÝ

ÖÆÈ¡°±Æø²¢Íê³ÉÅçȪʵÑ飨ͼÖмгÖ×°ÖþùÒÑÂÔÈ¥£©¡£

(1)д³öʵÑéÊÒÖÆÈ¡°±ÆøµÄ»¯Ñ§·½³Ìʽ£º                           

(2)ÊÕ¼¯°±ÆøÓ¦Ê¹Óà             ·¨£¬ÒªµÃµ½¸ÉÔïµÄ°±Æø¿ÉÑ¡Óà          ¸ÉÔï¼Á¡£

(3)ÈçºÎ¼ìÑéÉÕÆ¿Äڵİ±ÆøÒѾ­ÊÕ¼¯Âú£¿

                                                                          ¡£

ÓÃͼ1×°ÖýøÐÐÅçȪʵÑ飬Éϲ¿ÉÕÆ¿ÒÑ×°Âú¸ÉÔïµÄ°±Æø£¬Òý·¢Ë®ÉÏÅçµÄ²Ù×÷ÊÇ£º¼·Ñ¹½ºÍ·µÎ¹Ü£¬´ò¿ªÖ¹Ë®¼Ð¡£¸ÃʵÑéµÄÔ­ÀíÊÇ                                               ¡£

Ò»°ã×öÅçȪʵÑéʱ£¬Ë®¶¼²»¿ÉÄܽ«ÉÕÆ¿³äÂú£¬ÆäÖ÷ÒªÔ­ÒòÊÇ                                          

                                                                                          

Èç¹ûÖ»ÌṩÈçͼ2µÄ×°Öã¬Çë˵Ã÷Òý·¢ÅçȪµÄ·½·¨£º                                      

                                                                           ¡£             

£¨1£© 2NH4Cl+Ca(OH)2==CaCl2+NH3¡ü+H2O

(2)ÏòÏÂÅÅ¿ÕÆø·¨     ¼îʯ»Ò

£¨3£©½«ÊªÈóµÄºìɫʯÈïÊÔÖ½·ÅÔÚÉÕÆ¿¿Ú¹Û²ì£¬ÈôÊÔÖ½±äÀ¶£¬ËµÃ÷°±ÒÑÊÕÂú£¨ÆäËüºÏÀí´ð°¸Ò²µÃ·Ö£©

£¨4£©´ò¿ªÖ¹Ë®¼Ð£¬¼·Ñ¹½ºÍ·µÎ¹Ü£¬ÓÉÓÚ°±³£ÈÜÓÚË®£¬Ê¹Æ¿ÄÚѹǿ¼õС£¬¹ÊÐγÉÅçȪ;ÉÕÆ¿ÖÐÊÕ¼¯µ½µÄÆøÌåÖлìÓÐ¿ÕÆø£»´ò¿ªÖ¹Ë®¼Ð£¬ÓÃÈÈë½íÎæ×¡ÉÕÆ¿¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø