ÌâÄ¿ÄÚÈÝ


½«Ò»¶¨Á¿µÄ¾§ÌåA£¬¸ô¾ø¿ÕÆø¼ÓÈȵ½200¡æÊ±£¬AÈ«²¿·Ö½âΪµÈÎïÖʵÄÁ¿µÄËÄÖÖÆøÌå¡£ÕâËÄÖÖÎïÖÊÓëÆäËûµÄÏ໥ת»¯¹ØÏµÈçÏÂͼËùʾ¡£FºÍJÊÇÖÐѧ»¯Ñ§Öг£¼ûµÄÁ½ÖÖµ¥ÖÊ¡£HΪºì×ØÉ«ÆøÌ塣ͼÖв¿·Ö·´Ó¦Ìõ¼þ¼°Éú³ÉÎïûÓÐÁгö¡£Çë°´ÒªÇóÌî¿Õ£º

£¨1£©µ¥ÖÊFµÄ»¯Ñ§Ê½              

£¨2£©Ð´³öBºÍF·´Ó¦µÄ»¯Ñ§·½³Ìʽ                            £¬LºÍBµÄË®ÈÜÒº·´Ó¦µÄÀë×Ó·½³Ìʽ                                       £»

£¨3£©Ð´³öKÓëIµÄÏ¡ÈÜÒº·´Ó¦µÄÀë×Ó·½³Ìʽ                            

£¨4£©AµÄ»¯Ñ§Ê½Îª                         

£¨5£©¹¤ÒµÉÏÒÔÁòËáÑÇÌú¡¢Ï¡ÁòËáºÍÑÇÏõËáÄÆÎªÔ­ÁÏÀ´ÖƱ¸Ä³¸ßЧ¾»Ë®¼ÁFe(OH)SO4,·´Ó¦ÓÐGÉú³É£¬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ                       


£¨1£©O2 £»£¨2·Ö£©

£¨2£©4NH3+5O2 4NO+6H2O£¨2·Ö£© Fe3++3 NH3¡¤H2O = Fe(OH)3 +3NH4£«£¨2·Ö£©

£¨3£©3Fe3O4+28H++NO3¡ª=9Fe3++NO¡ü+14H2O£»£¨2·Ö£©

£¨4£©H5C2O4N£¨»òNH4HC2O4£© £¨3·Ö£©

£¨5£©2FeSO4 + 2NaNO2 + H2SO4 2Fe(OH)SO4 + Na2SO4 + 2NO¡ü£¨3·Ö£©


Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø