ÌâÄ¿ÄÚÈÝ

ijζÈʱ,Ag2SO4ÔÚË®ÖеijÁµíÈÜ½âÆ½ºâÇúÏßÈçͼËùʾ¡£¸ÃζÈÏÂ,ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ(¡¡¡¡)
A£®º¬ÓдóÁ¿SµÄÈÜÒºÖп϶¨²»´æÔÚAg+
B£®0.02 mol¡¤L-1µÄAgNO3ÈÜÒºÓë0.02 mol¡¤L-1µÄNa2SO4ÈÜÒºµÈÌå»ý»ìºÏ²»»áÉú³É³Áµí
C£®Ag2SO4µÄÈܶȻý³£Êý(Ksp)Ϊ1¡Á10-3
D£®aµã±íʾAg2SO4µÄ²»±¥ºÍÈÜÒº,Õô·¢¿ÉÒÔʹÈÜÒºÓÉaµã±äµ½bµã
B
AÏî,ÓÉÓÚ³ÁµíÈÜ½âÆ½ºâÊǸö¶¯Ì¬Æ½ºâ,¹Ê¼´Ê¹SŨ¶ÈÔÙ´ó,Ò²ÓÐÉÙÁ¿µÄAg+´æÔÚ,²»ÕýÈ·;BÏî,¸ù¾ÝͼÏñKsp(Ag2SO4)=(2¡Á10-4)2¡Á5¡Á104=2¡Á10-3;¶ø0.02 mol/L AgNO3ÈÜÒºÓë0.02 mol/L Na2SO4ÈÜÒºµÈÌå»ý»ìºÏ,c2(Ag+)¡Ác(S)=(0.01)2¡Á0.01=1¡Á10-6<2¡Á10-3,¹ÊûÓгÁµíÉú³É,ÕýÈ·;CÏî,ÓÉBÏî½âÎöÖª²»ÕýÈ·;DÏî,aµãµ½bµã,Èç¹ûÊÇÕô·¢µÄ»°,Ag+ºÍSŨ¶È¾ù»áÔö´ó,¶ø²»ÊÇÖ»Ôö´óSŨ¶È,D´í¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø