ÌâÄ¿ÄÚÈÝ

ijÌþA 0.2 mol ÔÚÑõÆøÖÐÍêȫȼÉÕºó£¬Éú³ÉCO2ºÍH2O¸÷1.2 mol¡£ÊԻشð£º

£¨1£©ÌþAµÄ·Ö×ÓʽΪ_____________¡£

£¨2£©Èôȡһ¶¨Á¿µÄÌþAÍêȫȼÉÕºó£¬Éú³ÉCO2ºÍH2O¸÷3 mol£¬ÔòÓÐ________gÌþA²Î¼ÓÁË·´Ó¦£¬È¼ÉÕʱÏûºÄ±ê×¼×´¿öϵÄÑõÆø___________L¡£

£¨3£©ÈôÌþA²»ÄÜʹäåË®ÍÊÉ«£¬µ«ÔÚÒ»¶¨Ìõ¼þÏÂÄÜÓëÂÈÆø·¢ÉúÈ¡´ú·´Ó¦£¬ÆäÒ»ÂÈÈ¡´úÎïÖ»ÓÐÒ»ÖÖ£¬ÔòÌþAµÄ½á¹¹¼òʽΪ__________________¡£

£¨4£©ÈôÌþAÄÜʹäåË®ÍÊÉ«£¬ÔÚ´ß»¯¼Á×÷ÓÃÏ£¬ÓëH2¼Ó³É£¬Æä¼Ó³É²úÎï¾­²â¶¨·Ö×ÓÖк¬ÓÐ4¸ö¼×»ù£¬ÌþA¿ÉÄÜÓеĽṹ¼òʽΪ__________________________________________¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø