ÌâÄ¿ÄÚÈÝ

ÔÚÈý¸ö2LºãÈݵÄÈÝÆ÷ÖУ¬·Ö±ð·¢Éú·´Ó¦A(g)+3B(g)2C(g)£¬5minºó¸÷ÈÝÆ÷·´Ó¦´ïƽºâ״̬,ÆäÖм×ÈÝÆ÷ÖÐAµÄÎïÖʵÄÁ¿Îª0.4mol¡£

 
·´Ó¦Ç°¸÷ÎïÖʵÄÎïÖʵÄÁ¿/mol
A
B
C
¼×
1
3
0
ÒÒ
0
0
2
±û
1.5
4.5
1
ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨    £©
A£®ÒÒÖÐ5minÄÚCµÄ·´Ó¦ËÙÂÊΪ0.12mol/(L¡¤min)
B£®´ïµ½Æ½ºâʱ£¬±ûÖÐAµÄŨ¶ÈÊǼ×ÖеÄ2±¶
C£®±ûÖз´Ó¦µÄƽºâ³£Êý´óÓÚ¼×Öз´Ó¦µÄƽºâ³£Êý
D£®´ïµ½Æ½ºâʱ£¬¼×ÒÒÁ½ÈÝÆ÷ÖÐCµÄÎïÖʵÄÁ¿°Ù·Öº¬Á¿ÏàµÈ

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨2010?˳ÒåÇøÒ»Ä££©½üÄêÀ´£¬Ì¼ºÍ̼µÄ»¯ºÏÎïÔÚÉú²úÉú»îʵ¼ÊÖÐÓ¦Óù㷺£®
£¨1£©¼×ÍéȼÉշųö´óÁ¿µÄÈÈ£¬¿É×÷ΪÄÜÔ´ÓÃÓÚÈËÀàµÄÉú²úºÍÉú»î£®
ÒÑÖª ¢Ù2CH4£¨g£©+3O2£¨g£©=2CO £¨g£©+4H2O£¨l£©¡÷H1=-1214.6KJ/mol
¢Ú2CO £¨g£©+O2£¨g£©=2CO2£¨g£©¡÷H2=-566kJ/mol
Ôò·´Ó¦CH4£¨g£©+2O2£¨g£©=CO2£¨g£©+2H2O £¨l£© µÄ¡÷H=
-890.3KJ/mol
-890.3KJ/mol
£®
£¨2£©½«Á½¸öʯīµç¼«²åÈËKOHÈÜÒºÖУ¬ÏòÁ½¼«·Ö±ðͨÈëCH4ºÍO2£¬¹¹³É¼×ÍéȼÁÏµç³Ø£®Í¨ÈëCH4µÄÒ»¼«£¬Æäµç¼«·´Ó¦Ê½ÊÇ£ºCH4+10OH--8e-=CO32-+7H2O£»Í¨ÈëO2µÄÒ»¼«£¬Æäµç¼«·´Ó¦Ê½ÊÇ
O2+4e_+2H2O=4OH-
O2+4e_+2H2O=4OH-
£®
£¨3£©ÈôÓÃʯī×öµç¼«µç½â500ml±¥ºÍʳÑÎË®£¬Ð´³öµç½â·´Ó¦µÄÀë×Ó·½³ÌʽΪ£º
2Cl-+2H2O
 Í¨µç 
.
 
H2¡ü+Cl2¡ü+2OH-
2Cl-+2H2O
 Í¨µç 
.
 
H2¡ü+Cl2¡ü+2OH-
£»µç½âÒ»¶Îʱ¼äºóÁ½¼«¹²ÊÕ¼¯µ½±ê×¼×´¿öÏÂµÄÆøÌå1.12L£¨²»¿¼ÂÇÆøÌåµÄÈܽ⣩£®Í£Ö¹Í¨µç£¬¼ÙÉ跴ӦǰºóÈÜÒºÌå»ý²»±ä£¬ÔòËùµÃÈÜÒºµÄpH=
13
13
£®
£¨4£©½«²»Í¬Á¿µÄCO £¨g£© ºÍH2O £¨g£© ·Ö±ðͨÈëµ½Ìå»ýΪ2LµÄºãÈÝÃܱÕÈÝÆ÷ÖУ¬½øÐз´Ó¦
CO £¨g£©+H2O £¨g£©?CO2£¨g£©+H2£¨g£©£¬µÃµ½ÈçÏÂÈý×éÊý¾Ý£º
ʵÑé×é ζÈ/¡æ ÆðʼÁ¿/mol ƽºâÁ¿/mol ´ïµ½Æ½ºâËù
Ðèʱ¼ä/min
H2O CO CO2 CO
1 650 2 4 1.6 2.4 5
2 900 1 2 0.4 1.6 3
3 900 a b c d t
¢ÙʵÑé1ÖÐÒÔ¦Ô£¨H2£© ±íʾµÄ·´Ó¦ËÙÂÊΪ
0.16mol?£¨L?min£©-1
0.16mol?£¨L?min£©-1
£®
¢ÚʵÑé2ÖÐµÄÆ½ºâ³£ÊýÊÇ
0.17
0.17
 £¨¼ÆËã½á¹û±£ÁôÁ½Î»Ð¡Êý£©£®
¢Û¸Ã·´Ó¦µÄÕý·´Ó¦Îª
·Å
·Å
£¨Ìî¡°Îü¡±»ò¡°·Å¡±£©ÈÈ·´Ó¦£®
¢ÜÈôʵÑé3Òª´ïµ½ÓëʵÑé2ÏàͬµÄƽºâ״̬£¨¼´¸÷ÎïÖʵÄÖÊÁ¿·ÖÊý·Ö±ðÏàµÈ£©£¬Ôòa¡¢bÓ¦Âú×ãµÄ¹ØÏµÊÇ
b=2a£¾l£¨»òa£¾0.5£¬b=2a£»»òb£¾1£¬b=2a£©
b=2a£¾l£¨»òa£¾0.5£¬b=2a£»»òb£¾1£¬b=2a£©
 £¨Óú¬a¡¢bµÄÊýѧʽ±íʾ£©£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø