ÌâÄ¿ÄÚÈÝ
ÏÖÓÐA¡¢B¡¢CÈýÖÖÆøÌ壬AÊÇÃܶÈ×îСµÄÆøÌ壬BÔÚͨ³£Çé¿öϳʻÆÂÌÉ«£¬´¿¾»µÄA¿ÉÒÔÔÚBÖа²¾²µØÈ¼ÉÕÉú³ÉC¡£°ÑÆøÌåBͨÈëµ½ÊÊÁ¿Ê¯»ÒÈéÖпÉÒԵõ½°×É«»ë×ÇÎïD¡£Çë¾Ý´Ë»Ø´ðÏÂÁÐÎÊÌ⣺
(1)д³öÏÂÁи÷·´Ó¦µÄ»¯Ñ§·½³Ìʽ¡£
¢Ù´¿¾»µÄAÔÚBÖа²¾²µØÈ¼ÉÕÉú³ÉC£º__________________________£»
¢Ú½«ÆøÌåBͨÈ뵽ˮÖУº_______________________________________£»
¢Û½«ÆøÌåBͨÈëµ½NaOHÈÜÒºÖУº______________________________£»
¢Ü½«ÆøÌåBͨÈëµ½ÊÊÁ¿Ê¯»ÒÈéÖУº________________________________¡£
(2)°ÑÈýÖÖÆøÌå·Ö±ðͨÈëËáÐÔÏõËáÒøÈÜÒºÖУ¬³öÏÖ°×É«³ÁµíµÄÆøÌåÊÇ£º________(ÓÃ×Öĸ±íʾ)¡£
(3)°×É«»ë×ÇÎïDÒò¾ßÓÐÆ¯°×ÐÔÓÖ³ÆÎª________£¬¸ÃÎïÖÊÔÚ¿ÕÆøÖÐÈÝÒ×±äÖʵÄÔÒòΪ(Óû¯Ñ§·½³Ìʽ±íʾ)________________ ___________________¡£
¡¾½âÎö¡¿¡¡¸ù¾ÝÌâÒâ¿ÉÖªBΪCl2£¬AΪH2£¬CΪHCl£¬DΪƯ°×·Û¡£
¡¾´ð°¸¡¿¡¡(1)¢ÙH2£«Cl2
2HCl
¢ÚCl2£«H2O===HCl£«HClO
¢ÛCl2£«2NaOH===NaCl£«NaClO£«H2O
¢Ü2Cl2£«2Ca(OH)2===CaCl2£«Ca(ClO)2£«2H2O
(2)BC
(3)Ư°×·Û¡¡Ca(ClO)2£«CO2£«H2O===CaCO3¡ý£«2HClO,2HClO
2HCl£«O2¡ü
Îíö²ÌìÆøÑÏÖØÓ°ÏìÈËÃǵÄÉú»î£¬ÆäÖеªÑõ»¯ÎïºÍÁòÑõ»¯ÎïÊÇÔì³ÉÎíö²ÌìÆøµÄÖ÷ÒªÔÒòÖ®Ò»¡£Ïû³ýµªÑõ»¯ÎïºÍÁòÑõ»¯ÎïÓжàÖÖ·½·¨¡£
£¨1£©ÓûîÐÔÌ¿»¹Ô·¨¿ÉÒÔ´¦ÀíµªÑõ»¯ÎijÑо¿Ð¡×éÏòijÃܱÕÈÝÆ÷ÖмÓÈëÒ»¶¨Á¿µÄ»îÐÔÌ¿ºÍNO£¬·¢Éú·´Ó¦£ºC(s)+2NO(g)
N2(g)+CO2(g) ¡÷H=Q kJ¡¤mol-1¡£ÔÚT1¡æÊ±£¬·´Ó¦½øÐе½²»Í¬Ê±¼ä²âµÃ¸÷ÎïÖʵÄŨ¶ÈÈçÏ£º
| ʱ¼ä(min) Ũ¶È£¨mol¡¤L-1£© | 0 | 10 | 20 | 30 | 40 | 50 |
| NO | 1.00 | 0.58 | 0.40 | 0.40 | 0.48 | 0.48 |
| N2 | 0 | 0.21 | 0.30 | 0.30 | 0.36 | 0.36 |
| CO2 | 0 | 0.21 | 0.30 | 0.30 | 0.36 | 0.36 |
¢Ù0¡«10 minÄÚ£¬NOµÄƽ¾ù·´Ó¦ËÙÂÊv(NO)=_______________________£¬T1¡æÊ±£¬¸Ã·´Ó¦µÄƽºâ³£ÊýK=______________________________¡£
¢Ú30 minºó£¬Ö»¸Ä±äijһÌõ¼þ£¬·´Ó¦ÖØÐ´ﵽƽºâ£¬¸ù¾ÝÉϱíÖеÄÊý¾ÝÅжϸıäµÄÌõ¼þ¿ÉÄÜÊÇ__________ (Ìî×Öĸ)¡£
a£®¼ÓÈëÒ»¶¨Á¿µÄ»îÐÔÌ¿ b£®Í¨ÈëÒ»¶¨Á¿µÄNO
c£®Êʵ±ËõСÈÝÆ÷µÄÌå»ý d£®¼ÓÈëºÏÊʵĴ߻¯¼Á
¢ÛÈô30 minºóÉý¸ßζÈÖÁT2¡æ£¬´ïµ½Æ½ºâʱ£¬ÈÝÆ÷ÖУ¬NO¡¢N2¡¢CO2µÄŨ¶ÈÖ®±ÈΪ5£º3£º3£¬ÔòQ______________ (Ìî¡°>¡±¡¢¡°=¡±»ò¡°<¡±)0¡£
£¨2£©NH3´ß»¯»¹ÔµªÑõ»¯ÎSCR£©¼¼ÊõÊÇĿǰӦÓÃ×î¹ã·ºµÄÑÌÆøµªÑõ»¯ÎïÍѳý¼¼Êõ¡£·´Ó¦ÔÀíÈçͼËùʾ£º
![]()
¢ÙÓÉͼ¼×¿ÉÖª£¬SCR¼¼ÊõÖеÄÑõ»¯¼ÁΪ_______________¡£ÒÑÖªc(NO2)£ºc(NO)=1:1ʱÍѵªÐ§¹û×î¼Ñ£¬ÈôÉú³É1 mol N2ʱ·´Ó¦·Å³öµÄÈÈÁ¿ÎªQ kJ¡£´Ëʱ¶ÔÓ¦µÄÍѵª·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽΪ__________________________¡£
¢ÚͼÒÒÊDz»Í¬´ß»¯¼ÁMnºÍCrÔÚ²»Í¬Î¶È϶ÔÓ¦µÄÍѵªÂÊ£¬ÓÉͼ¿ÉÖª¹¤ÒµÊ¹ÓõÄ×î¼ÑµÄ´ß»¯¼ÁºÍÏàÓ¦µÄζȷֱðΪ___________________________¡£
£¨3£©ÀûÓÃÅçÎí¸ÉÔï·¨ÍÑÁò¹¤ÒÕÊdzýÈ¥SO2µÄ³£¼û·½·¨£¬ÏȽ«º¬SO2µÄ·ÏÆøÈÜÓÚË®£¬ÔÙÓñ¥ºÍʯ»Ò½¬ÎüÊÕ¡£¸ÃζÈÏ£¬ÎüÊÕÒºÖÐc(Ca2+)Ò»Ö±±£³ÖΪ0.70 mol¡¤L-1£¬ÒÑÖªKsp(CaSO3)=1.4¡Á10-7£¬ÇóÎüÊÕºóÈÜÒºÖеÄSO32-µÄŨ¶È_______________¡££¨Ð´³ö¼ÆËã¹ý³Ì£¬½á¹û±£Áô2λÓÐЧÊý×Ö£©
¿ÕÆø´µ³ö·¨ÊÇ×îÔ繤ҵ»¯º£Ë®ÌáäåµÄ·½·¨£¬ÊʺϴӵÍŨ¶Èº¬äåÈÜÒºÖÐÌáÈ¡äå¡£
£¨1£©NaBrµÄµç×ÓʽÊÇ ¡£
£¨2£©·´Ó¦¢ÙÊǽ«Br¡ª×ª»¯ÎªBr2£¬·´Ó¦¢ÙµÄÀë×Ó·½³ÌʽÊÇ ¡£
£¨3£©Í¨Èë¿ÕÆø´µ³öBr2£¬²¢ÓÃNa2CO3ÎüÊÕµÄÄ¿µÄÊÇ ¡£
£¨4£©·´Ó¦¢ÚµÄ»¯Ñ§·½³ÌʽÊÇ ¡£
£¨5£©·´Ó¦¢ÛÖÐÿÉú³É3 mol Br2£¬×ªÒƵç×ÓµÄÎïÖʵÄÁ¿ÊÇ mol¡£
£¨6£©ÎªÁ˳ýÈ¥¹¤ÒµBr2ÖÐ΢Á¿µÄCl2£¬¿ÉÏò¹¤ÒµBr2ÖÐ £¨Ìî×Öĸ£©¡£
a£®Í¨ÈëHBr b£®¼ÓÈëNaBrÈÜÒº c£®¼ÓÈëNa2CO3ÈÜÒº d£®¼ÓÈëNa2SO3ÈÜÒº