ÌâÄ¿ÄÚÈÝ
ijÈÝ»ý¿É±äµÄÃܱÕÈÝÆ÷ÖÐÊ¢ÓÐ×ãÁ¿µÄA£¬Í¨ÈËÆøÌåB£¬·¢Éú·´Ó¦£º
A(s)+3B(g)
2C(g)+ D(g)£»¦¤H<0£¬ÔÚÒ»¶¨Î¶ȺÍѹǿÏ´ﵽƽºâ¡£ÈôƽºâʱCµÄÎïÖʵÄÁ¿Óë¼ÓÈëBµÄÎïÖʵÄÁ¿µÄ±ä»¯¹ØÏµÈçͼËùʾ¡£ ÔòÏÂÁÐ˵·¨ÖÐÕýÈ·µÄÊÇ
![]()
AÈô±£³Öѹǿ²»±ä£¬½µµÍζÈʱ£¬Í¼ÖнǶÈa½«±äС
BÈôÔö´óѹǿ£¬ËõСÈÝÆ÷µÄÌå»ý£¬Æ½ºâÏòÕý·´Ó¦·½ÏòÒÆ¶¯
CÈô±£³Öѹǿ²»±ä£¬ÔÙͨÈËB£¬ÔòÔٴδﵽƽºâʱÕý¡¢Äæ·´Ó¦ËÙÂʾùÔö´ó
DƽºâʱB¡¢CµÄÎïÖʵÄÁ¿Ö®±ÈΪ1£º2
D
¡¾½âÎö¡¿
AÖнµµÍζȣ¬Æ½ºâÕýÏòÒÆ¶¯£¬ËùÒÔͨÈëÏàͬµÄÁ¿B£¬Éú³ÉµÄC¸ü¶à£¬aÔö´ó£¬A´í£»¸Ã·´Ó¦ÎªÌå»ý²»±äµÄ·´Ó¦£¬Ôö´óѹǿ£¬Æ½ºâ²»Òƶ¯£¬B´í£»ºãѹµÄÌõ¼þÏ£¬Í¨ÈëB£¬ÎªµÈЧƽºâ£¬´ïµ½Æ½ºâ£¬ÕýÄæ·´Ó¦ËÙÂʲ»±ä£¬C´í£»´ÓͼÏñÖпÉÒÔ¿´³ö£¬±ÈÖµ1£º2£¬DÕýÈ·£»´ð°¸Ñ¡D¡£
̼¼°Æä»¯ºÏÎïÓй㷺µÄÓÃ;¡£
(1)½«Ë®ÕôÆøÍ¨¹ýºìÈȵÄ̼¼´¿É²úÉúË®ÃºÆø·´Ó¦Îª
C(s)£«H2O(g)
CO(g)£«H2(g)¡¡¦¤H£½£«131.3 kJ¡¤mol£1£¬
ÒÔÉÏ·´Ó¦´ïµ½Æ½ºâºó£¬ÔÚÌå»ý²»±äµÄÌõ¼þÏ£¬ÒÔÏ´ëÊ©ÓÐÀûÓÚÌá¸ßH2OµÄƽºâת»¯ÂʵÄÊÇ________¡£(ÌîÐòºÅ)
A£®Éý¸ßÎÂ¶È B£®Ôö¼Ó̼µÄÓÃÁ¿C£®¼ÓÈë´ß»¯¼Á D£®ÓÃCOÎüÊÕ¼Á³ýÈ¥CO
(2)ÒÑÖª£ºC(s)£«CO2(g)
2CO(g)¡¡¦¤H£½£«172.5 kJ¡¤mol£1£¬ÔòCO(g)£«H2O(g)
CO2(g)£«H2(g)µÄìʱ䦤H£½________¡£
(3)COÓëH2ÔÚÒ»¶¨Ìõ¼þÏ¿ɷ´Ó¦Éú³É¼×´¼£ºCO(g)£«2H2(g)
CH3OH(g)¡£¼×´¼ÊÇÒ»ÖÖȼÁÏ£¬¿ÉÀûÓü״¼Éè¼ÆÒ»¸öȼÁÏµç³Ø£¬ÓÃÏ¡ÁòËá×÷µç½âÖÊÈÜÒº£¬¶à¿×ʯī×÷µç¼«£¬¸Ãµç³Ø¸º¼«·´Ó¦Ê½Îª______________________________________¡£
ÈôÓÃ¸Ãµç³ØÌṩµÄµçÄܵç½â60 mL NaClÈÜÒº£¬ÉèÓÐ0.01 mol CH3OHÍêÈ«·Åµç£¬NaCl×ãÁ¿£¬ÇÒµç½â²úÉúµÄCl2È«²¿Òݳö£¬µç½âǰºóºöÂÔÈÜÒºÌå»ýµÄ±ä»¯£¬Ôòµç½â½áÊøºóËùµÃÈÜÒºµÄpH£½________¡£
(4)½«Ò»¶¨Á¿µÄCO(g)ºÍH2O(g)·Ö±ðͨÈëµ½Ìå»ýΪ2.0 LµÄºãÈÝÃܱÕÈÝÆ÷ÖУ¬·¢ÉúÒÔÏ·´Ó¦£ºCO(g)£«H2O(g)
CO2(g)£«H2(g)¡£µÃµ½ÈçÏÂÊý¾Ý£º
ζÈ/¡æ | ÆðʼÁ¿/mol | ƽºâÁ¿/mol | ´ïµ½Æ½ºâËù Ðèʱ¼ä/min | ||
H2O | CO | H2 | CO |
| |
900 | 1.0 | 2.0 | 0.4 | 1.6 | 3.0 |
ͨ¹ý¼ÆËãÇó³ö¸Ã·´Ó¦µÄƽºâ³£Êý(½á¹û±£ÁôÁ½Î»ÓÐЧÊý×Ö)________¡£¸Ä±ä·´Ó¦µÄijһÌõ¼þ£¬·´Ó¦½øÐе½t minʱ£¬²âµÃ»ìºÏÆøÌåÖÐCO2µÄÎïÖʵÄÁ¿Îª0.6 mol¡£ÈôÓÃ200 mL 5 mol/LµÄNaOHÈÜÒº½«ÆäÍêÈ«ÎüÊÕ£¬·´Ó¦µÄÀë×Ó·½³ÌʽΪ(ÓÃÒ»¸öÀë×Ó·½³Ìʽ±íʾ)_________________________
(5)¹¤ÒµÉú²úÊǰÑË®ÃºÆøÖеĻìºÏÆøÌå¾¹ý´¦Àíºó»ñµÃµÄ½Ï´¿H2ÓÃÓںϳɰ±¡£ºÏ³É°±·´Ó¦ÔÀíΪN2(g)£«3H2(g)
2NH3(g)¡¡¦¤H£½£92.4 kJ¡¤mol£1¡£ÊµÑéÊÒÄ£Ä⻯¹¤Éú²ú£¬·Ö±ðÔÚ²»Í¬ÊµÑéÌõ¼þÏ·´Ó¦£¬N2Ũ¶ÈËæÊ±¼ä±ä»¯Èçͼ¼×Ëùʾ¡£
![]()
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
¢ÙÓëʵÑé¢ñ±È½Ï£¬ÊµÑé¢ò¸Ä±äµÄÌõ¼þΪ________________________________¡£
¢ÚʵÑé¢ó±ÈʵÑé¢ñµÄζÈÒª¸ß£¬ÆäËûÌõ¼þÏàͬ£¬ÇëÔÚͼÒÒÖл³öʵÑé¢ñºÍʵÑé¢óÖÐNH3Ũ¶ÈËæÊ±¼ä±ä»¯µÄʾÒâͼ¡£
ÓÃÊÔÖ½¼ìÑ鯸ÌåÐÔÖÊÊÇÒ»ÖÖÖØÒªµÄʵÑé·½·¨¡£ÈçÏÂͼËùʾµÄʵÑéÖÐ(¿É¼ÓÈÈ)£¬ÏÂÁÐÊÔÖ½µÄÑ¡Óá¢ÏÖÏó¡¢¶ÔÓ¦½áÂÛ¶¼ÕýÈ·µÄÒ»ÏîÊÇ
![]()
Ñ¡Ïî | ÊÔ¼ÁB | ʪÈóµÄ ÊÔÖ½A | ÏÖÏó | ½áÂÛ |
A | µâË® | µí·ÛÊÔÖ½ | ±äÀ¶ | µâ¾ßÓÐÑõ»¯ÐÔ |
B | Ũ°±Ë®£¬Éúʯ»Ò | À¶É«Ê¯ÈïÊÔÖ½ | ±äºì | °±ÆøÎª¼îÐÔÆøÌå |
C | Na2SO3£¬ÁòËá | Æ·ºìÊÔÖ½ | ÍÊÉ« | SO2¾ßÓÐÆ¯°×ÐÔ |
D | Cu£¬Å¨ÏõËá | KI£µí·Û ÊÔÖ½ | ±äÀ¶ | NO2Ϊ ËáÐÔÆøÌå |