题目内容

已知:O2(g) = O2+(g)+e          H1=" +1175.7" kJ·mol-1
PtF6(g) =PtF6(g)+e      H2=" +771.1" kJ·mol-1
O2+(g)+PtF6(g) =O2PtF6(S) H3=" -482.2" kJ·mol-1
则反应O2(g)+PtF6(g) = O2PtF6 (s)的H

A.77.6 kJ B.-77.6 kJ·mol-1 C.+77.6kJ·mol-1D.-886.8kJ·mol-1

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