ÌâÄ¿ÄÚÈÝ

8£®°±Ë®ÊÇÒ»ÖÖ»ìºÏÎÆäÖк¬ÓеÄ΢Á£ºÜ¶à£®Çëд³ö°±Ë®Öк¬ÓеÄÀë×ÓÓÐNH4+¡¢OH-¡¢H+£¬º¬ÓеķÖ×ÓÓÐNH3•H2O¡¢H2O£®°±ÆøÊÇÒ»ÖÖ³£Óõϝ¹¤Ô­ÁÏ£¬Çëд³öʵÑéÊÒÖÆÈ¡°±ÆøµÄ»¯Ñ§·´Ó¦·½³Ìʽ£º2NH4Cl+Ca£¨OH£©2$\frac{\underline{\;\;¡÷\;\;}}{\;}$CaCl2+2NH3¡ü+2H2O£»ÒªµÃµ½¸ÉÔïµÄ°±Æø£¬Óüîʯ»Ò×ö¸ÉÔï¼Á£®

·ÖÎö °±ÆøÓëË®·´Ó¦Éú³ÉһˮºÏ°±£¬Ò»Ë®ºÏ°±ÎªÈõµç½âÖÊ£¬ÈÜÒºÖдæÔÚ笠ùÀë×Ó¡¢ÇâÑõ¸ùÀë×Ó¡¢Ò»Ë®ºÏ°±µÈ£¬ÊµÑéÊÒ¿ÉÓÃÂÈ»¯ï§ºÍÇâÑõ»¯¸ÆÔÚ¼ÓÈÈÌõ¼þÏÂÖÆ±¸°±Æø£¬Óüîʯ»Ò¸ÉÔÒԴ˽â´ð¸ÃÌ⣮

½â´ð ½â£º°±Ë®ÖдæÔÚNH3•H2O?NH4++OH-£¬°±Ë®Öк¬ÓеÄÀë×ÓÓÐNH4+¡¢OH-¡¢H+£¬º¬ÓеķÖ×ÓÓÐNH3•H2O¡¢H2O£¬ÊµÑéÊÒ¿ÉÓÃÂÈ»¯ï§ºÍÇâÑõ»¯¸ÆÔÚ¼ÓÈÈÌõ¼þÏÂÖÆ±¸°±Æø£¬·½³ÌʽΪ2NH4Cl+Ca£¨OH£©2$\frac{\underline{\;\;¡÷\;\;}}{\;}$CaCl2+2NH3¡ü+2H2O£¬°±ÆøÎª¼îÐÔÆøÌ壬¿ÉÓüîʯ»Ò¸ÉÔ
¹Ê´ð°¸Îª£ºNH4+¡¢OH-¡¢H+£»NH3•H2O¡¢H2O£»¼îʯ»Ò£®

µãÆÀ ±¾Ì⿼²é°±ÆøµÄÐÔÖÊ£¬Îª¸ßƵ¿¼µã£¬²àÖØ¿¼²éѧÉúµÄ·¢ÉúÄÜÁ¦£¬×¢Òâ°ÑÎÕһˮºÏ°±ÎªÈõµç½âÖʵÄÌØµãÒÔ¼°°±ÆøµÄʵÑéÊÒÖÆ·¨£¬ÄѶȲ»´ó£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
12£®ÎªÁËÔ¤·Àµâȱ·¦²¡£¬¹ú¼Ò¹æ¶¨Ã¿Ç§¿ËʳÑÎÖÐÓ¦º¬ÓÐ40¡«50mgµÄµâËá¼Ø£¨KIO3£©£®ÒÑÖªÔÚÈÜÒºÖÐIO3-¿ÉºÍI-·¢Éú·´Ó¦£ºIO3-+5I-+6H+¡ú3I2+3H2O£®ÎªÖ¤Ã÷ÔÚʳÑÎÖдæÔÚIO3-£¬²¢¼ìÑéijÖÖʳÑÎÊÇ·ñΪ¼ÓµâµÄºÏ¸ñ²úÆ·£¬Ä³Í¬Ñ§½øÐÐÁËÏÂÁÐʵÑ飮
ʵÑéÒ»£ºÈ¡42.8gµÄʳÑÎÑùÆ·£¬¼ÓË®ÍêÈ«Èܽ⣬ÓÃÏ¡ÁòËáËữºó¼ÓÈë×ãÁ¿µÄµâ»¯¼ØÈÜÒº£®ÓÃÏÂÃæÁ½ÖÖ·½·¨½øÐмìÑ飮
£¨1£©ÈôµÎ¼Óµí·Û£¬ÈÜÒº±äÀ¶£¬ËµÃ÷º¬ÓÐIO3-£®
£¨2£©Èô¼ÓÈëCCl4ÈÜÒº£¬³ä·ÖÕñµ´£¬Èô³öÏÖËÄÂÈ»¯Ì¼²ãΪ×ÏÉ«ÏÖÏ󣬿ÉÖ¤Ã÷½áÂÛ£®½øÐиÃʵÑéËùÐèµÄÒÇÆ÷ÊÇ·ÖҺ©¶·£®
ʵÑé¶þ£ºÔÚʵÑéÒ»ÖÐÈÜÒºÖмÓÈë100mL5.4¡Á10-4mol/LµÄÁò´úÁòËáÄÆ£¨Na2S2O3£©ÈÜҺǡºÃÓëI2·´Ó¦Í꣬ʹÀ¶É«ÍÊÈ¥£®I2+2Na2S2O3¡ú2NaI+Na2S4O6
£¨3£©ÓÃÁò´úÁòËáÄÆ¹ÌÌåÅäÖÃËùÐèÈÜÒºÓõ½µÄ²£Á§ÒÇÆ÷³ý½ºÍ·µÎ¹Ü¡¢ÉÕ±­Í⣬»¹Óв£Á§°ô¡¢100mLÈÝÁ¿Æ¿£®
£¨4£©ÈôÔÚÅäÖÆ¹ý³ÌÖУ¬³öÏÖÏÂÁÐÇé¿ö£¬Ê¹ÊµÑé½á¹û¡°Æ«µÍ¡±µÄÊÇBCD
A£®ËùÓÃÒÇÆ÷ÄÚ²¿ÓÐÉÙÁ¿Ë®·Ö
B£®Î´½øÐÐÏ´µÓ²Ù×÷
C£®¶¨ÈÝʱÑöÊÓ¹Û²ìÒºÃæ
D£®¼ÓÕôÁóˮʱ£¬²»É÷³¬¹ýÁ˿̶È
£¨5£©¼ÆËã¸Ã42.8gµÄʳÑÎÑùÆ·ÖꬵâËá¼Ø1.926mg£¬ÅжϸüӵâÑÎÊÇ£¨Ñ¡Ìî¡°ÊÇ¡±»ò¡°²»ÊÇ¡±£©ºÏ¸ñ²úÆ·£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø