ÌâÄ¿ÄÚÈÝ


¢ñ.ÏÂͼÖÐA¡¢B¡¢C·Ö±ðÊÇÈýÖÖÓлúÎïµÄ½á¹¹Ä£ÐÍ£º

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

(1)A¼°ÆäͬϵÎïµÄ·Ö×ÓʽÖеÄ̼ԭ×ÓÊýÓÃn±íʾ¡£µ±n£½_______ʱ£¬ÍéÌþ¿ªÊ¼³ö

ÏÖͬ·ÖÒì¹¹Ìå¡£BÄ£ÐÍÊÇÓлúÎïµÄ________Ä£ÐÍ¡£

(2)½á¹¹¼òʽΪµÄÓлúÎïÖУ¬·Ö×ÓÖÐ×î¶àÓР    ¸öÔ­×Ó¹²Ãæ¡£

(3)µÈÖÊÁ¿µÄA¡¢B¡¢CÈýÖÖÓлúÎïÍêȫȼÉÕÉú³ÉH2OºÍCO2£¬ÏûºÄÑõÆøµÄÌå»ý(Ïàͬ״

¿öÏÂ)×î´óµÄÊÇ________(Ìî·Ö×Óʽ)¡£

¢ò.ÔÚÓлúÎï·Ö×ÓÖУ¬²»Í¬ÇâÔ­×ӵĺ˴ʲÕñÇâÆ×Öиø³öµÄ·åÖµ(ÐźÅ)Ò²²»Í¬£¬¸ù¾Ý

·åÖµ(ÐźÅ)¿ÉÒÔÈ·¶¨ÓлúÎï·Ö×ÓÖÐÇâÔ­×ÓµÄÖÖÀàºÍÊýÄ¿¡£

(1)ÏÂÁÐÎïÖÊÖУ¬ÆäºË´Å¹²ÕñÇâÆ×Öиø³öµÄ·åÖµ(ÐźÅ)Ö»ÓÐÒ»¸öµÄÊÇ________¡£

A£®CH3COOH        B£® C(CH3)4           C£®CH3COOCH3       D£®CH3OH

(2)»¯ºÏÎïAºÍBµÄ·Ö×Óʽ¶¼ÊÇC2H4Br2£¬AµÄºË´Å¹²ÕñÇâÆ×ͼÈçÏÂͼËùʾ£¬ÔòAµÄ

½á¹¹¼òʽΪ________¡£

(3)Óú˴ʲÕñÇâÆ×µÄ·½·¨À´Ñо¿C2H6OµÄ½á¹¹£¬¼òҪ˵Ã÷¸ù¾ÝºË´Å¹²ÕñÇâÆ×µÄ½á¹û

À´È·¶¨C2H6O·Ö×ӽṹµÄ·½·¨ÊÇ_______________________            _ ¡£


¢ñ. (1)4 £¨1·Ö£© ±ÈÀý£¨1·Ö£© (2)  23£¨1·Ö£©  (3) CH4£¨1·Ö£©

¢ò.(1)B  £¨1·Ö£© (2)BrCH2CH2Br£¨1·Ö£©

(3)ÈôÆ×ͼÖиø³öÁË3¸öÎüÊÕ·å(ÐźÅ)£¬Ôò˵Ã÷C2H6OµÄ½á¹¹ÊÇCH3CH2OH£»ÈôÆ×ͼÖиø³öÁË1¸öÎüÊÕ·å(ÐźÅ)£¬Ôò˵Ã÷C2H6OµÄ½á¹¹ÊÇCH3OCH3£¨2·Ö£©


Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø