ÌâÄ¿ÄÚÈÝ

N2O5ÊÇÒ»ÖÖÐÂÐÍÏõ»¯¼Á£¬ÆäÐÔÖʺÍÖÆ±¸Êܵ½ÈËÃǵĹØ×¢¡£
£¨1£©N2O5Óë±½·¢ÉúÏõ»¯·´Ó¦Éú³ÉµÄÏõ»ù±½µÄ½á¹¹¼òʽÊÇ________________
£¨2£©2N2O5£¨g£©¡ú4NO2£¨g£©+O2£¨g£©;¦¤H£¾0
¢Ù·´Ó¦´ïƽºâºó£¬ÈôÔÙͨÈëÒ»¶¨Á¿µªÆø£¬ÔòN2O5µÄת»¯Âʽ«_______£¨Ìî¡°Ôö´ó¡±¡¢¡°¼õС¡±¡¢¡°²»±ä¡±£©
¢ÚϱíΪ·´Ó¦ÔÚT1ζÈϵIJ¿·ÖʵÑéÊý¾Ý£º
Ôò500 sÄÚN2O5µÄ·Ö½âËÙÂÊΪ_________
¢ÛÔÚT3ζÈÏ£¬·´Ó¦1000 sʱ²âµÃNO2µÄŨ¶ÈΪ4.98 mol¡¤L-1£¬ÔòT2______T1
£¨3£©ÏÂͼËùʾװÖÿÉÓÃÓÚÖÆ±¸N2O5£¬ÔòN2O5ÔÚµç½â³ØµÄ_________ÇøÉú³É£¬Æäµç¼«·´Ó¦Ê½Îª
_______________
£¨1£©¡°ÂÔ¡±
£¨2£©¢Ù²»±ä£»¢Ú0.00296 mol¡¤L-1¡¤s-1£»¢Û¡°£¼¡±»ò¡°Ð¡ÓÚ¡±
£¨3£©Òõ¼«£»N2O4+2HNO3-2e-=2N2O5+2H+
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
¢ñ£®X¡¢Y¡¢ZÊǶÌÖÜÆÚÔªËØµÄÈýÖÖ³£¼ûÑõ»¯ÎX¸úË®·´Ó¦¿ÉÉú³ÉÒ»ÖÖ¾ßÓл¹Ô­ÐԵIJ»Îȶ¨µÄ¶þÔªËᣬ¸ÃËáµÄ»¯Ñ§Ê½ÊÇ
H2SO3
H2SO3
£»YºÍX×é³ÉÔªËØÏàͬ£¬YÓëË®·´Ó¦Éú³ÉM£¬×ãÁ¿MµÄŨÈÜÒºÓë3.2g CuÔÚ¼ÓÈÈÌõ¼þϳä·Ö·´Ó¦£¬ÆäÖб»»¹Ô­µÄMµÄÎïÖʵÄÁ¿Îª
0.05mol
0.05mol
£®¹Ì̬Z¿ÉÓ¦ÓÃÓÚÈ˹¤½µÓ꣬0.5mol?L-1ZÓëNaOH·´Ó¦ËùµÃµÄÕýÑÎË®ÈÜÒºÖУ¬Àë×ÓŨ¶È´Ó´óµ½Ð¡µÄ˳ÐòΪ
C£¨Na+£©£¾C£¨CO32- £©£¾C£¨OH-£©£¾C£¨HCO3-£©£¾C£¨H+£©
C£¨Na+£©£¾C£¨CO32- £©£¾C£¨OH-£©£¾C£¨HCO3-£©£¾C£¨H+£©
£®
¢ò£®N2O5ÊÇÒ»ÖÖÐÂÐÍÏõ»¯¼Á£¬ÆäÐÔÖʺÍÖÆ±¸Êܵ½ÈËÃǵĹØ×¢£®ÏÖÒÔH2¡¢O2¡¢ÈÛÈÚÑÎNa2CO3×é³ÉµÄȼÁÏµç³Ø£¬ÆäÖÐYΪCO2£»²ÉÓõç½â·¨ÖƱ¸N2O5£¬×ܵķ´Ó¦·½³ÌʽΪ£ºN2O4+2HNO3=2N2O5+H2£¬×°ÖÃÈçͼËùʾ£®
д³öʯīIµç¼«ÉÏ·¢Éú·´Ó¦µÄµç¼«·´Ó¦Ê½
H2+CO32--2e-=CO2+H2O
H2+CO32--2e-=CO2+H2O
£®
ÔÚµç½â³ØÖÐÉú³ÉN2O5µÄµç¼«·´Ó¦Ê½Îª
N2O4+2HNO3-2e-=2N2O5+2H+
N2O4+2HNO3-2e-=2N2O5+2H+
£®
¢ó£®ÑÌÆøµÄÍÑÁò£¨³ýSO2£©¼¼ÊõºÍÍÑÏõ£¨³ýNOx£©¼¼Êõ¶¼ÊÇ»·¾³¿ÆÑ§Ñо¿µÄÈȵ㣮
£¨1£©ÑÌÆøÍÑÁò¡¢ÍÑÏõ¶Ô»·¾³µÄÒâÒå
·ÀÖ¹ËáÓê¡¢¹â»¯Ñ§ÑÌÎíµÄ·¢Éú
·ÀÖ¹ËáÓê¡¢¹â»¯Ñ§ÑÌÎíµÄ·¢Éú
£®
£¨2£©Ä¿Ç°£¬¿ÆÑ§¼ÒÕýÔÚÑо¿Ò»ÖÖÒÔÒÒÏ©×÷Ϊ»¹Ô­¼ÁµÄÍÑÏõ£¨NO£©Ô­Àí£¬ÆäÍÑÏõ»úÀíʾÒâͼÈçͼ1£®

ÍÑÏõÂÊÓëζȡ¢¸ºÔØÂÊ£¨·Ö×ÓɸÖд߻¯¼ÁµÄÖÊÁ¿·ÖÊý£©µÄ¹ØÏµÈçͼ2Ëùʾ£®
¢Ùд³ö¸ÃÍÑÏõÔ­Àí×Ü·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º
6NO+3O2+2C2H4
 ´ß»¯¼Á 
.
 
3N2+4CO2+4H2O
6NO+3O2+2C2H4
 ´ß»¯¼Á 
.
 
3N2+4CO2+4H2O
£®¢ÚΪ´ïµ½×î¼ÑÍÑÏõЧ¹û£¬Ó¦²ÉÈ¡µÄÌõ¼þÊÇ
350¡æ¡¢¸ºÔØÂÊ3%
350¡æ¡¢¸ºÔØÂÊ3%
£®

¢ñ.¸Ç˹¶¨ÂÉÔÚÉú²úºÍ¿ÆÑ§Ñо¿ÖÐÓкÜÖØÒªµÄÒâÒå¡£ÓÐЩ·´Ó¦µÄ·´Ó¦ÈÈËäÈ»ÎÞ·¨Ö±½Ó²âµÃ£¬µ«¿Éͨ¹ý¼ä½ÓµÄ·½·¨²â¶¨¡£ÏÖ¸ù¾ÝÏÂÁеÄ5¸ö·´Ó¦(Óɰ±Æø¡¢HClºÍË®ÖÆ±¸NH4C1Ë®ÈÜÒº)¡£ÇëÅжϷ´Ó¦¢ÜµÄ·´Ó¦ÈÈ£º¦¤H£½                          ¡£

    ¢Ù NH3(g) + HCl(g) = NH4Cl(s) ¦¤H=£­176kJ¡¤mol¨C1

    ¢Ú NH3(g) + H2O(l) = NH3(aq)  ¦¤H=£­35.1 kJ¡¤mol¨C1

   ¢Û HCl(g) + H2O(l) = HCl(aq) ¦¤H=£­72.3 kJ¡¤mol¨C1

   ¢Ü NH4C1(s) + H2O(1) = NH4C1(aq)

   ¢Ý NH3(aq) + HCl(aq) = NH4C1(aq) ¦¤H= £­52.3 kJ¡¤mol¨C1

¢ò. N2O5ÊÇÒ»ÖÖÐÂÐÍÏõ»¯¼Á£¬ÆäÐÔÖʺÍÖÆ±¸Êܵ½ÈËÃǵĹØ×¢¡£ÏÖÒÔH2¡¢O2¡¢ÈÛÈÚÑÎNa2CO3×é³ÉµÄȼÁÏµç³Ø£¬²ÉÓõç½â·¨ÖƱ¸N2O5£¬×°ÖÃÈçͼËùʾ£¬ÆäÖÐYΪCO2¡£

д³öʯīIµç¼«ÉÏ·¢Éú·´Ó¦µÄµç¼«·´Ó¦Ê½                              ¡£

ÔÚµç½â³ØÖÐÉú³ÉN2O3µÄµç¼«·´Ó¦Ê½Îª                                 ¡£

¢ó.ÑÌÆøµÄÍÑÁò£¨³ýSO2£©¼¼ÊõºÍÍÑÏõ£¨³ýNOx£©¼¼Êõ¶¼ÊÇ»·¾³¿ÆÑ§Ñо¿µÄÈȵ㡣

¢ÅÑÌÆøÍÑÁò¡¢ÍÑÏõµÄ»·¾³ÒâÒåÊÇ          ¡£

(2)Ŀǰ£¬¿ÆÑ§¼ÒÕýÔÚÑо¿Ò»ÖÖÒÔÒÒÏ©×÷Ϊ»¹Ô­¼ÁµÄÍÑÏõ£¨NO£©Ô­Àí£¬ÆäÍÑÏõ»úÀíʾÒâͼÈçÏÂͼ1£¬ÍÑÏõÂÊÓëζȡ¢¸ºÔØÂÊ£¨·Ö×ÓɸÖд߻¯¼ÁµÄÖÊÁ¿·ÖÊý£©µÄ¹ØÏµÈçͼ2Ëùʾ¡£

¢Ùд³ö¸ÃÍÑÏõÔ­Àí×Ü·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º      ¡£¢ÚΪ´ïµ½×î¼ÑÍÑÏõЧ¹û£¬Ó¦²ÉÈ¡µÄÌõ¼þÊÇ     ¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø