ÌâÄ¿ÄÚÈÝ


ÏÂÁÐÐðÊöÕýÈ·µÄÊÇ ( )

A£®ÔÚ0.10 mol¡¤L£­1 NaHCO3ÈÜÒºÖУºc(H+)£«c(H2CO3)£½c(OH£­)£«c(CO)

B£®¼×ÍéµÄ±ê׼ȼÉÕÈÈÊÇ890.3 kJ¡¤mol-1£¬Ôò¼×ÍéȼÉÕµÄÈÈ»¯Ñ§·½³ÌʽÊÇ£º

CH4(g)£«2O2(g)£½CO2(g)£«2H2O(g) ¡÷H£½£­890.3 kJ¡¤mol£­1

C£®ÓÃÍ­×÷µç¼«µç½âCuSO4ÈÜÒº£º2Cu2+£«2H2O 2Cu£«O2¡ü£«4H+

D£®ÒÔKOHΪµç½âÖÊÈÜÒºµÄ¼×´¼È¼ÁÏµç³ØµÄ¸º¼«µç¼«·´Ó¦Ê½£º

CH3OH£­6e£­£«H2O£½CO2¡ü£«6H+

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

ϱíÁгöÁË¢Ù¡«¢âÊ®ÖÖÔªËØÔÚÖÜÆÚ±íÖеÄλÖãº

¡¡¡¡¡¡×å

ÖÜÆÚ

¢ñA

¢òA

¢óA

¢ôA

¢õA

¢öA

¢÷A

0

2

¢Ù

¢Ú

3

¢Û

¢Ü

¢Ý

¢Þ

¢ß

¢à

¢â

4

¢á

¢ÅÉÏÊö¢Ù¡«¢âÊ®ÖÖÔªËØÖУ¨ÓÃÔªËØ·ûºÅÌî¿Õ£©£º

¹¹³ÉÓлúÎïµÄÖ÷ÒªÔªËØÊÇ¡¡¡¡¡¡¡¡¡¡¡¡¡¡£¬¹¹³ÉÑÒʯÓëÐí¶à¿óÎïµÄ»ù±¾ÔªËØÊÇ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£¬

»¯Ñ§ÐÔÖÊ×î²»»îÆÃµÄÔªËØ¡¡¡¡¡¡¡¡¡¡¡¡¡¡£¬ÆøÌ¬Ç⻯ÎïµÄË®ÈÜÒº³Ê¼îÐÔµÄÔªËØ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£

¢ÆÉÏÊö¢Ù¡«¢áÔªËØµÄ×î¸ß¼ÛÑõ»¯Îï¶ÔÓ¦µÄË®»¯ÎïÖУº

¼îÐÔ×îÇ¿µÄÎïÖʵĵç×ÓʽΪ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£¬

ËáÐÔ×îÇ¿µÄÎïÖʵĻ¯Ñ§Ê½Îª¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£

¢ÇÈôÒÔÔªËØ¢ÜºÍ¢ÝµÄµ¥ÖÊΪµç¼«£¬ÓëÔªËØ¢ÛµÄ×î¸ß¼ÛÑõ»¯Îï¶ÔÓ¦µÄË®»¯ÎïµÄË®ÈÜÒº×é³ÉÔ­µç³Ø£¬Ôò¢ÜµÄµ¥ÖÊÔÚ´ËÔ­µç³ØÖÐ×÷¡¡¡¡¡¡¡¡¡¡¼«£¨Ìî¡°Õý¡±»ò¡°¸º¡±£©

¢ÈÔªËØ¢ßµÄijÑõ»¯ÎïΪÓд̼¤ÐÔÆøÎ¶µÄÎÞÉ«ÆøÌ壬ÆäÇ⻯ÎïΪÓгô¼¦µ°ÆøÎ¶µÄÎÞÉ«ÆøÌå¡£ÈôÕâÁ½ÖÖÆøÌå»ìºÏ£¬»áÉú³ÉÒ»ÖÖµ­»ÆÉ«·ÛÄ©¡£´Ë·´Ó¦»¯Ñ§·½³ÌʽΪ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£Èô´Ë·´Ó¦ÖÐÑõ»¯²úÎïµÄÖÊÁ¿Îª3.2g£¬Ôò·´Ó¦ÖÐ×ªÒÆµÄµç×ÓÊýΪ¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£¨ÌîÊýÖµ£©¡£

¢ÉÔªËØ¢àºÍÔªËØ¢áÁ½Õߺ˵çºÉÊýÖ®²îÊÇ¡¡¡¡¡¡¡¡¡¡£¬ÕâÁ½ÖÖÔªËØÖзǽðÊôÐÔ½ÏÈõµÄÔªËØÊÇ¡¡¡¡¡¡¡¡¡¡£¨ÌîÔªËØÃû³Æ£©£¬ÄÜ˵Ã÷ÕâÁ½ÖÖÔªËØµÄ·Ç½ðÊôÐÔÇ¿ÈõµÄʵÑéÊÂʵÊÇ£¨ÓÃÀë×Ó·½³Ìʽ±íʾ£©

¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø