ÌâÄ¿ÄÚÈÝ
Áò´úÁòËáÄÆ(Na2S2O3)Ë׳Ʊ£ÏÕ·Û£¬¿ÉÓÃÓÚÕÕÏàÒµ×÷¶¨Ó°¼Á£¬Ò²¿ÉÓÃÓÚÖ½½¬Æ¯°××÷ÍÑÂȼÁµÈ¡£ÊµÑéÊÒ¿Éͨ¹ýNa2S¡¢Na2CO3ºÍSO2¹²Í¬·´Ó¦À´ÖÆÈ¡Na2S2O3¡£[΢ÈíÓû§19]
![]()
ͼ1 ͼ2
£¨1£©Ð´³öͼ1ËùʾװÖÃÖÐÈý¾±Æ¿ÖÐÓÉ·´Ó¦ÖÆÈ¡Na2S2O3µÄ»¯Ñ§·½³Ìʽ_ ¡ø ___¡£
È罫·ÖҺ©¶·ÖеÄH2SO4¸Ä³ÉŨÑÎËᣬÔòÈý¾±ÉÕÆ¿ÄÚ³ýNa2S2O3Éú³ÉÍ⣬»¹ÓÐ__¡ø___(Ìѧʽ)ÔÓÖÊÉú³É¡£
£¨2£©Îª²â¶¨ËùµÃ±£ÏÕ·ÛÑùÆ·ÖÐNa2S2O3¡¤5H2OµÄÖÊÁ¿·ÖÊý£¬¿ÉÓñê×¼µâÈÜÒº½øÐе樣¬·´Ó¦·½³ÌʽΪ2Na2S2O3£«I2===2NaI£«Na2S4O6¡£
¢Ù ÀûÓÃKIO3¡¢KIºÍHCl¿ÉÅäÖÆ±ê×¼µâÈÜÒº¡£Ð´³öÅäÖÆÊ±Ëù·¢Éú·´Ó¦µÄÀë×Ó·½³Ìʽ£º________¡ø___________¡£
¢Ú ׼ȷ³ÆÈ¡Ò»¶¨ÖÊÁ¿µÄNa2S2O3¡¤5H2OÑùÆ·ÓÚ×¶ÐÎÆ¿ÖУ¬¼ÓË®Èܽ⣬²¢µÎ¼Ó__¡ø ×÷ָʾ¼Á£¬ÓÃËùÅäÖÆµÄ±ê×¼µâÈÜÒºµÎ¶¨¡£µÎ¶¨Ê±ËùÓõIJ£Á§ÒÇÆ÷³ý×¶ÐÎÆ¿Í⣬»¹ÓÐ__¡ø___¡£
¢Û ÈôµÎ¶¨Ê±Õñµ´²»³ä·Ö£¬¸Õ¿´µ½ÈÜÒº¾Ö²¿±äÉ«¾ÍÍ£Ö¹µÎ¶¨£¬Ôò»áʹÑùÆ·ÖÐNa2S2O3¡¤5H2OµÄÖÊÁ¿·ÖÊýµÄ²âÁ¿½á¹û___¡ø___(Ìî¡°Æ«¸ß¡±¡°Æ«µÍ¡±»ò¡°²»±ä¡±)¡£
£¨3£©±¾ÊµÑé¶ÔNa2SµÄ´¿¶ÈÒªÇó½Ï¸ß£¬ÀûÓÃͼ2ËùʾµÄ×°Öÿɽ«¹¤Òµ¼¶µÄNa2SÌá´¿¡£ÒÑÖªNa2S³£ÎÂÏÂ΢ÈÜÓھƾ«£¬¼ÓÈÈʱÈܽâ¶ÈѸËÙÔö´ó£¬ÔÓÖʲ»ÈÜÓھƾ«¡£Ìá´¿²½ÖèÒÀ´ÎΪ£º
¢Ù ½«ÒѳÆÁ¿ºÃµÄ¹¤ÒµNa2S·ÅÈëÔ²µ×ÉÕÆ¿ÖУ¬²¢¼ÓÈëÒ»¶¨ÖÊÁ¿µÄ¾Æ¾«ºÍÉÙÁ¿Ë®£»
¢Ú °´Í¼2ËùʾװÅäËùÐèÒÇÆ÷£¬ÏòÀäÄý¹ÜÖÐͨÈëÀäÈ´Ë®£¬¡ø ½ø ¡ø³ö£¨ÓÃ×Öĸ¡°a¡±¡¢¡°b¡±Ìî¿Õ£©Ë®Ô¡¼ÓÈÈ£»¸ß ¿¼ ×Ê Ô´ Íø
¢Û ´ý__¡ø___ʱ£¬Í£Ö¹¼ÓÈÈ£¬½«ÉÕÆ¿È¡Ï£»
¢Ü ________________¡ø___________£»
¢Ý ______________¡ø__________£»
¢Þ ½«ËùµÃ¹ÌÌåÏ´µÓ¡¢¸ÉÔµÃµ½Na2S¡¤9H2O¾§Ìå¡£
(1) 2Na2S£«Na2CO3£«4SO2===3Na2S2O3£«CO2¡¡£¨2·Ö£© NaCl£¨1·Ö£©
(2) ¢Ù IO
£«5I££«6H£«===3I2£«3H2O£¨2·Ö£©
¢Ú µí·ÛÈÜÒº¡¡ËáʽµÎ¶¨¹Ü£¨2·Ö£©¡¡¢Û Æ«µÍ £¨1·Ö£©
(3) ¢Ú b a £¨1·Ö£©
¢Û ÉÕÆ¿ÖйÌÌå²»ÔÙ¼õÉÙ£¨2·Ö£©¡¡¢Ü ³ÃÈȹýÂË£¨2·Ö£©
¡¡ ¢Ý ½«ËùµÃÂËÒºÀäÈ´½á¾§£¬¹ýÂË£¨2·Ö£©
²¿·ÖÈõËáµÄµçÀëÆ½ºâ³£ÊýÈçÏÂ±í£º
| ÈõËá | HCOOH | HCN | H2CO3 |
| µçÀëÆ½ºâ³£Êý £¨25¡æ£© | Ka=1.77¡Á10-4 | Ka=4.9¡Á10-10 | Ka1=4.3¡Á10-7 Ka2=5.6¡Á10-11 |
ÏÂÁÐÑ¡ÏîÕýÈ·µÄÊÇ[΢ÈíÓû§14]
A. 2CN-+H2O+CO2=2HCN+CO32-
B. Öк͵ÈÌå»ý¡¢µÈpHµÄHCOOHºÍHCNÏûºÄNaOHµÄÁ¿Ç°ÕßСÓÚºóÕß
C. ÎïÖʵÄÁ¿Å¨¶ÈÏàµÈµÄHCOONaºÍKCNÈÜÒºÖУ¬c(Na£«)£c(HCOO£) < c(K£«)£c(CN£)
D. c(NH4+) ÏàµÈµÄHCOONH4ÈÜÒº¡¢NH4CNÈÜÒº¡¢NH4HCO3ÈÜÒºÖУ¬
c(NH4HCO3)>c(NH4CN) >c(HCOONH4)