ÌâÄ¿ÄÚÈÝ


½µµÍ´óÆøÖÐCO2µÄº¬Á¿¼°ÓÐЧµØ¿ª·¢ÀûÓà CO2£¬Ä¿Ç°¹¤ÒµÉÏÓÐÒ»ÖÖ·½·¨ÊÇÓÃCO2À´Éú²ú¼×´¼È¼ÁÏ¡£ÎªÌ½¾¿·´Ó¦Ô­Àí£¬ÏÖ½øÐÐÈçÏÂʵÑ飬ÔÚÌå»ýΪ1LµÄºãÈÝÃܱÕÈÝÆ÷ÖУ¬³äÈë1mol CO2ºÍ3mol H2£¬Ò»¶¨Ìõ¼þÏ·¢Éú·´Ó¦£ºCO2(g)£«3H2(g) CH3OH(g)£«H2O(g)¡¡¦¤H £½£­49.0kJ/mol¡£²âµÃCO2ºÍCH3OH(g)µÄŨ¶ÈËæÊ±¼ä±ä»¯ÈçͼËùʾ¡£



(1)´Ó·´Ó¦¿ªÊ¼µ½Æ½ºâ£¬ÇâÆøµÄƽ¾ù·´Ó¦ËÙÂÊv(H2)£½________mol/(L¡¤min)£»

(2)ÇâÆøµÄת»¯ÂÊ£½________£»

(3)¸Ã·´Ó¦µÄƽºâ³£ÊýΪ________(±£ÁôСÊýµãºó2λ)£»

(4)ÏÂÁдëÊ©ÖÐÄÜʹƽºâÌåϵÖÐn(CH3OH)/n(CO2)Ôö´óµÄÊÇ________¡£

A£®Éý¸ßζÈ

B£®³äÈëHe(g)£¬Ê¹ÌåϵѹǿÔö´ó

C£®½«H2O(g)´ÓÌåϵÖзÖÀë³öÈ¥

D£®ÔÙ³äÈë1mol H2

(5)µ±·´Ó¦´ïµ½Æ½ºâʱ£¬H2µÄÎïÖʵÄÁ¿Å¨¶ÈΪc1£¬È»ºóÏòÈÝÆ÷ÖÐÔÙ¼ÓÈëÒ»¶¨Á¿H2£¬´ý·´Ó¦ÔÙÒ»´Î´ïµ½Æ½ºâºó£¬H2µÄÎïÖʵÄÁ¿Å¨¶ÈΪc2£¬Ôòc1________c2µÄ¹ØÏµ(Ìî¡°>¡±¡¢¡°<¡±»ò¡°£½¡±)¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø