题目内容
甲、乙两人登上同样高度的楼层,甲重400N,乙重500N.若甲上楼用20s,乙上楼用10s,则甲、乙两人做功之比为______,做功的功率之比为______.
∵登上同样高度的楼层,
∴根据W=Gh得:W甲:W乙=G甲h:G乙h═G甲:G乙=400N:500N=4:5;
∵P=
,
∴P甲:P乙=
:
=
×
=
×
=2:5.
故答案为:4:5;2:5.
∴根据W=Gh得:W甲:W乙=G甲h:G乙h═G甲:G乙=400N:500N=4:5;
∵P=
| W |
| t |
∴P甲:P乙=
| W甲 |
| t甲 |
| W乙 |
| t乙 |
| W甲 |
| W乙 |
| t乙 |
| t甲 |
| 4 |
| 5 |
| 10s |
| 20s |
故答案为:4:5;2:5.
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