ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿½üЩÄêÖйúµÄ¸ßÌú¼¼Êõ·¢Õ¹Ñ¸ÃÍ£¬¾©»¦¸ßÌúµÄ¿ªÍ¨¸üÊÇÌåÏÖÁËÖйúÔÚ¸ÃÏî¼¼ÊõµÄÁìÏȵØÎ»¡£

£¨1£©¸ßËÙÁгµÔëÉùºÜС£¬ËüÊÇ´Ó·ÀÖ¹ÔëÉù·½Ãæ×ÅÊÖ¿ØÖƵ쬶¬ÌìºÍÏÄÌìÔëÉùµÄ´«²¥ËÙ¶È________£¨Ìî¡°Ïàͬ¡±»ò¡°²»Í¬¡±£©£¬ÔëÉùÊÇÒÔ________Ϊµ¥Î»À´±íʾǿÈõµÈ¼¶µÄ£»

£¨2£©Èô¸ßËÙÁгµÔÈËÙͨ¹ý³¤1.75kmµÄijÇÅÓÃʱ30s£¬Áгµ³¤350m£¬Ôò¸ÃÁгµËÙ¶ÈÊÇ________m/s£¬ÁгµÖÐ×ùÒÎÉϵÄijλ³Ë¿Íͨ¹ý´ËÇŵÄʱ¼äΪ________s¡£

¡¾´ð°¸¡¿²»Í¬ dB£¨·Ö±´£© 70 25

¡¾½âÎö¡¿

(1)[1]ÉùÒôÐèÒª½éÖÊÀ´´«²¥£¬²»Í¬µÄ½éÖÊÖУ¬ÉùÒô´«²¥µÄËÙ¶ÈÊDz»Í¬µÄ£¬Ò»°ãÇé¿öÏ£¬ÉùÒôÔÚ¹ÌÌåÖд«²¥µÄ×î¿ì£¬ÔÚÆøÌåÖд«²¥µÄ×îÂý£»Í¬Ò»ÖÖ½éÖÊÖУ¬Î¶Ȳ»Í¬Ê±ÉùÒôµÄ´«²¥ËÙ¶ÈÒ²²»Í¬£¬¹Ê¶¬ÌìºÍÏÄÌìÔëÉùµÄ´«²¥ËٶȲ»Í¬£»

[2]ÔëÉùÊÇÒÔdB£¨·Ö±´£©Îªµ¥Î»À´±íʾǿÈõµÈ¼¶µÄ£»

(2)[3]ÁгµÍêÈ«¹ýÇÅͨ¹ýµÄ·³Ì£º

£¬

¸ÃÁгµËÙ¶ÈÊÇ

£»

[4]ÁгµÖÐ×ùÒÎÉϵÄijλ³Ë¿Íͨ¹ý´ËÇŵÄʱ¼äΪ£º

¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø