ÌâÄ¿ÄÚÈÝ

10£®Ä³ÊµÑéС×éÀûÓÃÈçͼËùʾµÄʵÑé×°ÖôÖÂÔ²âÁ¿À¯ÖòµÄÈÈÖµq£¬Í¼ÖÐAΪ´©ÓÐСľ¹÷µÄÈÝÆ÷£¨ÄÚ×°ÓÐË®£©£¬BΪϲ¿¿ªÁËÐí¶àÍ¨Æø¿×µÄÕÖ×Ó£®
ÎïÀíÁ¿²âÁ¿Öµ
ÈÝÆ÷ÖÐË®µÄÖÊÁ¿m/g150
ÈÝÆ÷ÖÐË®µÄ³õÎÂt1/¡æ25
ÈÝÆ÷ÖÐË®µÄÄ©ÎÂt2/¡æ40
ȼÉÕǰÀ¯ÖòµÄÖÊÁ¿m1/g20.6
ȼÉÕºóÀ¯ÖòµÄÖÊÁ¿m2/g20
 
£¨1£©¹Û²ìʵÑé×°ÖÿÉÖª£¬ÊµÑéС×éͬѧÊÇͨ¹ý²âÁ¿Ë®ÎüÊÕµÄÈÈÁ¿¼ä½Ó²âÁ¿À¯ÖòȼÉշųöµÄÈÈÁ¿£®
£¨2£©ÒªÍê³É±¾ÊµÑ飬³ýÁËͼÖеÄʵÑéÆ÷²Ä£¬»¹ÐèÒªµÄ²âÁ¿¹¤¾ßÊÇζȼƺÍÌìÆ½£®
£¨3£©Ä³´ÎʵÑé²âµÃµÄÊý¾ÝÈçÏÂ±í£¬Ôò´ÖÂÔ²âµÃÕâÖ§À¯ÖòµÄÈÈÖµq=1.575¡Á107J/kg£®
£¨4£©±¾ÊµÑé²â³öµÄÈÈÖµ»á±ÈÕæÊµÖµ¸üС£®

·ÖÎö £¨1£©¸ù¾ÝͼʾʵÑé×°Ö÷ÖÎö´ðÌ⣻
£¨2£©ÊµÑé¹ý³ÌÖÐÐèÒª²âË®µÄζȡ¢Ë®µÄÖÊÁ¿¡¢À¯ÖòµÄÖÊÁ¿£¬¾Ý´ËÑ¡ÔñʵÑéÆ÷²Ä£»
£¨3£©À¯ÖòÊͷŵÄÈÈÁ¿µÈÓÚË®ËùÎüÊÕµÄÈÈÁ¿£¬ÓÉÈÈÁ¿¹«Ê½ÓëȼÉÕÖµ¹«Ê½¿ÉÒÔÇó³öÀ¯ÖòµÄȼÉÕÖµ£»
£¨4£©À¯ÖòȼÉÕÊͷŵÄÈÈÁ¿Ã»Óб»Ë®ÍêÈ«ÎüÊÕ£¬À¯Öò¿ÉÄÜûÓÐÍêȫȼÉÕ£¬¾Ý´Ë·ÖÎöȼÉÕÖµµÄ²âÁ¿ÖµÓëÕæÊµÖµ¼äµÄ¹ØÏµ£®

½â´ð ½â£º
£¨1£©ÓÉʵÑé×°ÖÿÉÖª£¬À¯ÖòȼÉÕ¸øË®¼ÓÈÈ£¬Í¨¹ý²âÁ¿AÈÝÆ÷ÖÐË®Éý¸ßµÄζȺÍË®µÄÖÊÁ¿¿ÉÒÔ¼ä½Ó²âÁ¿À¯ÖòȼÉշųöµÄÈÈÁ¿£»
£¨2£©ÒªÍê³É±¾ÊµÑ飬ÐèÒª²âÁ¿Ë®µÄζÈÓëË®ºÍÀ¯ÖòµÄÖÊÁ¿£¬Òò´Ë»¹ÐèҪζȼÆÓëÌìÆ½£»
£¨3£©ÕâÖ§À¯ÖòµÄÈÈÖµq=$\frac{{Q}_{·Å}}{{m}_{À¯}}$=$\frac{{Q}_{Îü}}{{m}_{À¯}}$=$\frac{{c}_{Ë®}{m}_{Ë®}¡÷{t}_{Ë®}}{{m}_{À¯}}$=$\frac{4.2¡Á1{0}^{3}J/£¨kg•¡æ£©¡Á0.15kg¡Á£¨40¡æ-25¡æ£©}{0.0206kg-0.020kg}$=1.575¡Á107J/kg£»
£¨4£©ÊµÑé¹ý³ÌÖÐÀ¯ÖòȼÉշųöµÄÈÈÁ¿Ã»ÓÐÈ«²¿±»Ë®ÎüÊÕ£¬Òò´ËʵÑé²â³öµÄÈÈÖµ±ÈÕæÊµÖµÐ¡£®
¹Ê´ð°¸Îª£º£¨1£©Ë®ÎüÊÕµÄÈÈÁ¿£»£¨2£©Î¶ȼƣ»ÌìÆ½£»£¨3£©1.575¡Á107£»£¨4£©Ð¡£®

µãÆÀ ·ÖÎöÇå³þͼʾÇé¾°£¬È·¶¨ÊµÑéÔ­ÀíÓëʵÑéÄ¿µÄ¼´¿ÉÕýÈ·½âÌ⣮

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
15£®Ä³Ð¡×éͬѧÀûÓùâ¾ß×ù½øÐС°Ì½¾¿Í¹Í¸¾µ³ÉÏñ¹æÂÉ¡±µÄʵÑ飺
£¨1£©½«À¯Öò¡¢Í¹Í¸¾µ¡¢¹âÆÁÒÀ´Î·ÅÔÚ¹â¾ß×ùÉÏ£¬µãȼÀ¯Öòºó£¬Ó¦µ÷ÕûÖòÑæ¡¢Í¸¾µºÍ¹âÆÁµÄÖÐÐÄ´óÖÂÔÚͬһ¸ß¶ÈÉÏ£®
£¨2£©ÒÑÖªËùÓõÄ͹͸¾µµÄ½¹¾àf=15cm£¬ÈçͼËùʾ£¬ÒªÊ¹À¯ÖòÔÚ¹âÆÁÉϳÉÇåÎúµÄÏñ£¬ÔÚÀ¯Öò¡¢Í¹Í¸¾µºÍ¹âÆÁÈýÕßÖУ¬Ö»Òƶ¯ÆäÖÐÒ»¸öµÄλÖã¬ÆäÓàÁ½¸ö²»¶¯£¬¿ÉÐеĴëÊ©ÊÇ£ºÍ¹Í¸¾µÏòÓÒÒÆ£®
£¨3£©Èç¹û°Ñ͹͸¾µ¹Ì¶¨ÔÚ¹â¾ß×ùÉÏ50cm¿Ì¶ÈÏß´¦£¬½«À¯ÖòÒÆÖÁ10cm¿Ì¶ÈÏß´¦£¬Òƶ¯¹âÆÁ£¬µ±¹âÆÁÉϳÊÏÖÖòÑæÇåÎúµÄÏñʱ£¬¸ÃÏñÊǵ¹Á¢¡¢ËõСµÄʵÏñ£»µ±ÖòÑæ·ÅÔÚ¾à͹͸¾µ12cm´¦Ê±£¬ÔÚ͹͸¾µÁíÒ»²àǰºóÒÆ¶¯¹âÆÁ£¬²»ÄÜ£¨Ñ¡Ìî¡°ÄÜ¡±»ò¡°²»ÄÜ¡±£©ÔÚ¹âÆÁÉϵõ½Ïñ£®
£¨4£©ÊµÑéÖУ¬È¼ÉÕµÄÀ¯ÖòÖð½¥±ä¶Ì£¬¹âÆÁÉϵÄÏñ»áÖð½¥ÏòÉÏ£¨Ìî¡°ÉÏ¡±»ò¡°Ï¡±£©Òƶ¯£¬ÎªÁËʹÏñ³ÉÔÚ¹âÆÁµÄÖÐÐÄ£¬¿É½«À¯ÖòÏòÉÏ£¨Ìî¡°ÉÏ¡±»ò¡°Ï¡±£©µ÷Õû£®
£¨5£©·ÖÎöʵÑéÊý¾Ý¿ÉÖª£¬µ±ÎïÌåͨ¹ý͹͸¾µ³ÉʵÏñʱ£¬Îï¾àÔö´ó£¬Ïñ¾à¼õС£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø